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lidiya [134]
2 years ago
14

Simplify mentally 4867.293 ÷ 1000

Mathematics
1 answer:
Marat540 [252]2 years ago
5 0

Step-by-step explanation:

20htff5tgtgtgtgtf5ddrtfy g huhh

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-7y - 3 - 2y= -5(y + 3)
Nana76 [90]

Answer:

y=-1(1)/(5)

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Multi-step K is the midpoint of JL, JL=4x-2, and JK=7. Find x, KL, and JL
ddd [48]
If K is midpoint of JL then JK = 0.5JL

JL = 4x - 2; JK = 7

The equation:
0.5(4x - 2) = 7
2x - 1 = 7      |add 1 to both sides
2x = 8        |divide both sides by 2
<u>x = 4</u>

<u>JL</u> = 4(4) - 2 = 16 - 2 = <u>14</u>

<u>KL</u> = JK =<u> 7</u>
7 0
3 years ago
HELP!!
Kazeer [188]

Answer:

(D)Lucita's estimate is too high.

6 0
3 years ago
A total of 579 tickets were sold for the school play they were either adult tickets or student tickets. there were 71 fewer stud
stepan [7]

Answer: 325

Step-by-step explanation:

Student tickets: x

Adult tickets: x + 71

Total: 579

x + x + 71 = 579

2x + 71 = 579

2x = 579 - 71

2x = 508

x = 508/2

x = 254

Adult tickets = x + 71 = 254 + 71 = 325

P.S. Hope it helps. If you have any questions, feel free to ask them here. I'll be happy to help! Have a wonderful day!

4 0
2 years ago
Write the equation of a parabola whose focus is at (-7, 3) and whose directrix is the line x = -3.
Sav [38]

Check the picture below.

now, let's keep in mind that, the vertex is half-way between the focus point and the directrix, it's a "p" distance from each other.

since this horizontal parabola is opening to the left-hand-side, "p" is negative, notice in the picture, "p" is 2 units, and since it's negative, p = -2.

its vertex is half-way between those two guys, so that puts the vertex at (-5, 3)

\bf \textit{parabola vertex form with focus point distance} \\\\ \begin{array}{llll} 4p(x- h)=(y- k)^2 \\\\ 4p(y- k)=(x- h)^2 \end{array} \qquad \begin{array}{llll} vertex\ ( h, k)\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} h=-5\\ k=7\\ p=-2 \end{cases}\implies 4(-2)[x-(-5)]=[y-7]^2 \\\\\\ -8(x+5)=(y-7)^2\implies x+5=\cfrac{(y-7)^2}{-8}\implies \boxed{x=-\cfrac{1}{8}(y-7)^2-5}

7 0
3 years ago
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