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saul85 [17]
3 years ago
5

100 points! A company makes triangular plates for individual slices of pizza. For each plate, the base is 9 inches and the heigh

t is 14 inches. The area of the top of the plate is ____ inches squared.
Mathematics
1 answer:
daser333 [38]3 years ago
3 0
To find the area you would had to do a an triangle formula so the final answer would be 63 inches
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At a sport clubhouse the coach wants to rope off a rectangular area that is adjacent to the building. He uses the length of the
Furkat [3]

Answer:

w < 8 meters ( w must be greater than 0 because length cannot be 0)

Step-by-step explanation:

One side with building is 23 meters, the other opposite side also will be 23 meters (with rope).

Let width (remaining 2 sides) be "w", he has AT MOST 39 meters of rope, so we can write:

Rope Needed = 23 + 2w < 39

Simplifying:

23 + 2w < 39\\2w < 39 - 23\\2w < 16\\w < 8

The range of possible values of w is  w meters (of course w has to be greater than 0)

5 0
3 years ago
Put the following equation of a line into slope-intercept form, reducing all fractions. 6x+2y=8
djyliett [7]
6x+2y=8
2y=-6x +8
y=-3x+4
4 0
3 years ago
A line passes through (3, -2) and (6,2), Write an equation for the line in point-slope form.
Harrizon [31]

y+2=4/3(x-3)

4x-3y=18

6 0
3 years ago
Write the number 3,2, and 8 addition sentence. Show two more way to find the sum.
Alexxx [7]
This doesn't make sense
6 0
3 years ago
Please help me compute standard deviation! Here is the problem, as written.
aleksandr82 [10.1K]

Answer:

The standard deviation for the income of super shoppers is 76.12.

Step-by-step explanation:

The formula to compute the standard deviation for the grouped data probability distribution is:

\sigma=\sqrt{\sum [(x-\mu)^{2}\cdot P(x)]}

Here,

<em>x</em> = midpoints

\mu=\sum x\cdot P(x)

Consider the Excel table attached below.

The mean is:

\mu=\sum x\cdot P(x)=32.3

Compute the standard deviation as follows:

\sigma=\sqrt{\sum [(x-\mu)^{2}\cdot P(x)]}

   =\sqrt{259.71}\\\\=76.1155204\\\\\approx 76.12

Thus, the standard deviation for the income of super shoppers is 76.12.

3 0
3 years ago
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