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saul85 [17]
4 years ago
5

100 points! A company makes triangular plates for individual slices of pizza. For each plate, the base is 9 inches and the heigh

t is 14 inches. The area of the top of the plate is ____ inches squared.
Mathematics
1 answer:
daser333 [38]4 years ago
3 0
To find the area you would had to do a an triangle formula so the final answer would be 63 inches
You might be interested in
Step by step
Damm [24]

Answer:

6x+1<9-2x

6x+2x<9-1

8x<8

x<1

2x-1 ≤ 5x+20

2x-5x≤20+1

-3x≤21

x≥-7

3-(2x-7) ≤ 34-6x

3-2x+7 ≤ 34-6x

-2x+6x ≤ 34-3-7

4x ≤ 24

x ≤ 6

6 0
3 years ago
A factory buys 10% of its components from suppliers B and the rest from supplier C. It is known that 6% of the components it buy
Aleks [24]

Answer:

The percentage of the components bought from supplier C that are faulty = 88%

Complete Question:

A factory buys 10% of its components from supplier A, 30% from supplier B,and the rest from supplier C. it is known that 6% of the components it buys are faulty. of the components bought from supplier A, 9% are faulty and of the components bought from supplier B, 3% are faulty.

find the percentage of the components bought from supplier C that are faulty ?

Step-by-step explanation:

Let x be the total components bought by the factory

Components supplied by A = 10% of x

Components supplied by B = 30% of x

The rest supplied by C:

Percentage supplied by C = 100-(30+10) = 100-40 = 60%

Components supplied by C = 60% of x

% of all faulty components = 6%

Amount of faulty component = 6% of x

faulty components from A= 9%

Amount of faulty component from A= 9% × (6% of x) = 0.0054x

faulty components from B= 3%

Amount of faulty component from A= 3% × (6% of x) = 0.0018x

Amount of faulty component from C = (6% of x) - (0.0054x+0.0018x)

= 0.06x - 0.0072x

= 0.0528x

Let the percentage of the components bought from supplier C that are faulty = y%

y% × 6% of x = 0.0528x

y% × 0.06x = 0.0528x

y% = 0.0528x/0.06x

y% = 0.88 = 88%

The percentage of the components bought from supplier C that are faulty = 88%

3 0
4 years ago
These box plots show the basketball scores for two teams.
Arisa [49]

The most appropriate statement is the interquartile range for the Wolverines, 30 is less than the IQR for the panthers, 40.

<h3>What is the correct statement?</h3>

The box plot is used to show the distribution of data. The box plot can be used to determine the range, interquartile range and median of the data set.

The range is the difference between the two ends of the whiskers.

Range for the Wolverines = 96 - 35 = 61

Range for the Panthers = 107 - 33 = 74

The interquartile range is the difference between the first and third lines on the box

IQR for the Wolverines = 85 - 55 = 30

Range for the Panthers = 90 - 50 = 40

To learn more about box plots, please check: brainly.com/question/1523909

#SPJ1

6 0
2 years ago
Walk 3 miles Per hour to school which is 1.5 miles away
satela [25.4K]

Answer:

Well if your going 3miles per hour and it 1.5 hours than it would take about...half an hour 30mins

Step-by-step explanation:

3 0
3 years ago
If 10% of men are bald, what is the probability that fewer than 100 in a random sample of 818 men are bald? (Answers must be in
Greeley [361]

Answer: the probability that fewer than 100 in a random sample of 818 men are bald is 0.9830

Step-by-step explanation:

Given that;

p = 10% = 0.1

so let q = 1 - p = 1 - 0.1 = 0.9

n = 818

μ = np = 818 × 0.1 = 81.8

α = √(npq) = √( 818 × 0.1 × 0.9 ) = √73.62 = 8.58

Now to find P( x < 100)

we say;

Z = (X-μ / α) = ((100-81.8) / 8.58) = 18.2 / 8.58 = 2.12

P(x<100) = P(z < 2.12)

from z-score table

P(z < 2.12) = 0.9830

Therefore the probability that fewer than 100 in a random sample of 818 men are bald is 0.9830

4 0
3 years ago
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