Answer:
a. Ed/eD
b. RF=0.12
Explanation:
The alleles for genes D/d and E/e are:
- D_: only on neck spikes
- dd: along back spikes
- E_: long spikes
- ee: short spikes
After testcrossing a double heterozygote (DdEe x ddee) there are 4 types of offspring, two of them much more abundant than the other two. The homozygous recessive parent can only produce <em>ed</em> gametes, so the phenotypes of the offspring depend on the gametes that the double heterozygous parent produced.
The offspring was:
- Ed/ed 79
- ed/ed 12
- ED/ed 10
- eD/ed 76
Total: 177
a) This result suggests that the genes are linked. Since recombination is a rare event, the most abundant phenotypes always come from the parental gametes, and the least abundant come from the recombinant gametes.
<u>Therefore, the genotype of the doube heterozygote parent was </u><u><em>Ed/eD</em></u><u>.</u>
b) Recombination frequency (RF) = Recombinants / Total
RF = (12+10)/177
<u>RF = 0.12</u>
I think the correct answer from the choices listed above is the second option. The term that would refer to the accumulation of persistent toxins in our body would be body burden. It <span>can be the result of long-term or short-term storage of toxins. Hope this answers the question.</span>
Heart disease
Heart disease is the leading cause of death in the United States, and forces many to apply for disability benefits every year.
It is true that there must be equipoise in order to justify conducting a clinical trial. They need first to have a equipoise so that they will justify conducting a clinical trial. Clinical trial is a research about whether the medical treatment or strategy is acceptance or safe and effective for human beings. The answer is True.
