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3 years ago

What is -1/4(8k^{2} - 16k) - 10k^{2} +15)

Mathematics

1 answer:

pogonyaev3 years ago

5 0

Answer:

-2x^2 + 4k - 10k^2 + 15

Step-by-step explanation:

-1/4(8k^2 - 16)-10k^2 + 15

-1/4 × 4 (2x^2 - 4k)-10k^2 +15

-(2x^2 - 4k)-10k^2 +15

-2x^2 + 4k - 10k^2 +15

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Kia rides her bicycle at 20 miles per hour. Which equation represents the situation?

sergejj [24]

Answer:

(A)d=20h

Step-by-step explanation:

If Kia rides her bike at 20 miles per hour.

20 miles per hour is referred to as the Kia's Speed.

Now we know that:

$$Speed=\frac{Distance \:Travelled}{Time \:taken}$

Given:

Number of hours traveled=h
Distance traveled=d
Speed = 20 mph

Substituting these three into the formula above, we have:

$20=\dfrac{d}{h}\\$

Cross multiply

d=20h

The correct option is A.

7 0

3 years ago

A tortoise is walking in the desert. It walks for 2 minutes at a speed of 5.12 meters per minute. For how many meters does it wa

Gnesinka [82]

What you have to do is multiply 5.12*2
10.24 meters

5 0

4 years ago

So if you can do expressions with rational numbers, what is the answer to -½+-0.5?

jek_recluse [69]

Answer:

-1

Step-by-step explanation:

The sum of -1/2 and -5/10 is -1.

4 0

3 years ago

Simplify, state all restrictions.

Kipish [7]

The simplified expression is $\frac{1 - x - y}{x + y}$ and the restriction is $y \ne -x$

<h3>How to simplify the expression?</h3>

The expression is given as:

$\frac{x - y}{4x^2 - 8xy + 3y^2} \div \frac{2x + y}{2x - 3y} \times \frac{4x^2 - y^2}{x^2 - y^2} -1$

Express x^2 - y^2 as (x + y)(x - y) and factorize other expressions

$\frac{x - y}{(2x - y)(2x - 3y)} \div \frac{2x + y}{2x - 3y} \times \frac{4x^2 - y^2}{(x - y)(x + y)} -1$

Rewrite the expression as products

$\frac{x - y}{(2x - y)(2x - 3y)} \times \frac{2x - 3y}{2x + y} \times \frac{4x^2 - y^2}{(x - y)(x + y)} -1$

Cancel out the common factors

$\frac{1}{(2x - y)} \times \frac{1}{2x + y} \times \frac{4x^2 - y^2}{(x + y)} -1$

Express 4x^2 - y^2 as (2x - y)(2x + y)

$\frac{1}{(2x - y)} \times \frac{1}{2x + y} \times \frac{(2x - y)(2x + y)}{(x + y)} -1$

Cancel out the common factors

$\frac{1}{x + y} -1$

Take the LCM

$\frac{1 - x - y}{x + y}$

Hence, the simplified expression is $\frac{1 - x - y}{x + y}$ and the restriction is $y \ne -x$