All categories

3 years ago

Find the product of two numbers whose sum is 11 and difference is 3.

Mathematics

2 answers:

mart [117]3 years ago

7 0

Answer:

a. 7 and 4

b. 28

Step-by-step explanation:

7 minus 4 is 3

7 plus 4 is 11

7 times 4 is 28

beks73 [17]3 years ago

4 0

Answer: 28

Step-by-step explanation: Hope this helps:)

You might be interested in

What 4.2 times 0.7 /a is 294 /b is 2.94 /c 29.4

zvonat [6]

Answer:

29.4

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Find the value of x.<br> I need help please!

Blababa [14]

Answer:

Step-by-step explanation:

Keep in mind that exterior angles are mentioned. So let's find the interior ones. Note that the interior and exterior angles are forming straight lines. So something plus 84 equals 180 degrees.

180-84=96

180-120=60

The sum of three angles of a triangle is 180 degrees. X is an angle. So we can form an equation to represent this. Then just solve for x!

96+60+x=180

156+x=180

x=24

8 0

3 years ago

What is the solution of y − 4x = 0 and 3x + 6y = 9?

Elden [556K]

You solve this by plugging one equation into the other. Usually you have to rewrite one equation to make this work. In this case I choose to rewrite y-4x=0 as y=4x.

After plugging it into the second, you get:

3x + 6*4x = 9 => 27x = 9 => x=1/3

Putting this solution back into y=4x gives us y=4/3

4 0

3 years ago

Two problems here I need solved! I need every step, so please have that with your answers!!

Free_Kalibri [48]

QUESTION 1

We want to solve,

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x^{2}-6x+8}$

We factor the denominator of the fraction on the right hand side to get,

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x^{2}-4x - 2x+8}.$

This implies
$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x(x-4) - 2(x - 4)}.$

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{(x-4)(x - 2)}$

We multiply through by LCM of
$(x-4)(x - 2)$

$(x - 2) + x(x-4) = 2$

We expand to get,

$x - 2 + {x}^{2} - 4x= 2$

We group like terms and equate everything to zero,

${x}^{2} + x - 4x - 2 - 2 = 0$

We split the middle term,

${x}^{2} + - 3x - 4 = 0$

We factor to get,

${x}^{2} + x - 4x- 4 = 0$

$x(x + 1) - 4(x + 1) = 0$

$(x + 1)(x - 4) = 0$

$x + 1 = 0 \: or \: x - 4 = 0$

$x = - 1 \: or \: x = 4$

But
$x = 4$
is not in the domain of the given equation.

It is an extraneous solution.

$\therefore \: x = - 1$
is the only solution.

QUESTION 2

$\sqrt{x+11} -x=-1$

We add x to both sides,

$\sqrt{x+11} =x-1$

We square both sides,

$x + 11 = (x - 1)^{2}$

We expand to get,

$x + 11 = {x}^{2} - 2x + 1$

This implies,

${x}^{2} - 3x - 10 = 0$

We solve this quadratic equation by factorization,

${x}^{2} - 5x + 2x - 10 = 0$

$x(x - 5) + 2(x - 5) = 0$

$(x + 2)(x - 5) = 0$

$x + 2 = 0 \: or \: x - 5 = 0$

$x = - 2 \: or \: x = 5$

But
$x = - 2$
is an extraneous solution

$\therefore \: x = 5$

7 0

3 years ago

3. Write the standard equation of the circle with the given center that passes through the given

bearhunter [10]

Answer:

D is correct.

Step-by-step explanation:

(x + 2)^2 + (y - 6)^2 = r^2

(-2+2)^2 + (10 - 6)^2 = r^2

r^2= (10 - 6)^2

r^2=16

5 0

3 years ago