Answer: P(x > - 0.23) = 0.41
Step-by-step explanation:
Since we are assuming that the readings at freezing on a batch of thermometers are normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = the readings at freezing on a batch of thermometers.
µ = mean temperature reading
σ = standard deviation
From the information given,
µ = 0°C
σ = 1.00°C
the probability of obtaining a reading less than -0.23°C is expressed as
P(x > - 0.23)
For x = - 0.23
z = (- 0.23 - 0)/1 = - 0.23
Looking at the normal distribution table, the probability corresponding to the z score is 0.41
Answer:
75
Step-by-step explanation:
Giving Q was not necessary because you aren't doing P(Q) or anything like that....
Anyways,
Since you're doing p(8), you would replace the x's with 8s.
So your final answer would be 75.
Answer:c
Explanation: well 79.95-20%=63.96
12 x g + 1
Hope this help you
