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Papessa [141]
2 years ago
8

Find the area of a triangle whose sides are 5 m, 6 m and 9m,( use root 2 =-1.41 m)​

Mathematics
1 answer:
dlinn [17]2 years ago
4 0

The area of the triangle is 14.1 square meters

<h3>How to determine the triangle area?</h3>

The side lengths are given as:

5m, 6m and 9m

Calculate the semi-perimeter (s) using

s = (5 + 6 + 9)/2

Evaluate

s = 10

The area is then calculated as:

Area = \sqrt{s(s -a)(s-b)(s-c)

This gives

Area = \sqrt{10 * (10 -5)(10-6)(10-9)

Evaluate the products

Area = \sqrt{200

Evaluate the exponent

Area = 14.1

Hence, the area of the triangle is 14.1 square meters

Read more about areas at:

brainly.com/question/27683633

#SPJ1

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Answer:

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Step-by-step explanation:

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What is the measure of ZA?<br> 100"<br> A. 30<br> B. 50°<br> C. 70°<br> D. 130°
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You , malakhi , yanis , nyla , Aaliyah go to a new tapas restaurant in jamaica , queens each of you order 6 small dishes that ea
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3 years ago
The frequency table shows how many visits to the library students in a school have made in the last month.
vfiekz [6]
<h3>Answer:  2.8</h3>

=======================================================

Explanation:

Multiply each visit count with their corresponding frequency.

Examples:

  • 0*12 = 0 for the first row.
  • 1*366 = 366 for the second row
  • 2*53 = 106 for the third row

and so on...

I recommend making a third column like this

\begin{array}{|c|c|c|} \cline{1-3}\text{Visits} & \text{Frequency} & \text{Visits*Frequency}\\\cline{1-3}0 & 12 & 0\\\cline{1-3}1 & 366 & 366\\\cline{1-3}2 & 53 & 106\\\cline{1-3}3 & 52 & 156\\\cline{1-3}4 & 155 & 620\\\cline{1-3}5 & 243 & 1215\\\cline{1-3}\end{array}

That way you can keep track of all the results in an organized way.

Then add everything in the third column

0+366+106+156+620+1215 = 2463

Divide this sum over the total frequency (12+366+53+52+155+243 = 881) and we'll get the mean

2463/881 = 2.7956867

Rounding to one decimal place gets us to 2.8 as the final answer.

-------------

The much longer way to do this is to imagine 12 copies of "0", 366 copies of "1", 53 copies of "2", and so on. We'll have an extremely large data set of 881 items inside it. As you can see, this second method is definitely not recommended to actually carry out. Rather it's helpful to have this as a thought experiment to see why we revert to multiplication instead.

Eg: Imagine adding 155 copies of "4". A shortcut is to simply say 4*155 = 620

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