Answer:
Step-by-step explanation:
We are given the following in the question:
The needle size should not be too big and too small.
The diameter of the needle should be 1.65 mm.
We design the null and the alternate hypothesis
Sample size, n = 35
Sample mean, 
= 1.64 mm
Sample standard deviation, s = 0.07 mm
Type I error:
- It is the error of rejecting the null hypothesis when it is true.
- It is also known as false positive error.
- It is the rejecting of a true null hypothesis.
Thus, type I error in this study would mean we reject the null hypothesis that the average diameter is 1.65 mm but actually the average diameters of the needle is 1.65 mm.
Thus, average diameter is 1.65 mm and we decide that it is not 1.65 mm.
The data set represents the prices, in dollars, of the items students are selling for a fundraiser. 1, 1, 2, 3, 3, 4, 4, 4, 5, 5
lidiya [134]
To produce a box plot, we need the lowest and highest value from the data set. We also need the lower quartile (
), median (
), and upper quartile (
).
All these data and the box plot is shown in the diagram below
The domain and range of the given function are equal to (0, 3.85) and (0, 18.75) respectively.
<h3>How to calculate the domain of the function?</h3>
In this exercise, you're given the following function h(t) = -4.87t² + 18.75t. Next, we would equate the function to zero (0) to determine its domain as follows:
0= -4.87t² + 18.75t.
4.87t(-t + 3.85) = 0
t = 0 or t = 3.85.
Therefore, the domain is 0 ≤ t ≤ 3.85 or (0, 3.85).
<h3>How to calculate the range of the function?</h3>
h(t) = -4.87t² + 18.75t
h(t) = -4.87(t² - 3.85t + 3.85 - 3.85)
h(t) = -4.87(t - 1.925)² + 18.05
Therefore, the range is 0 ≤ h ≤ 18.05 or (0, 18.75).
Read more on domain here: brainly.com/question/17003159
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Solve for x
Divide both sides by -4
X= - 10/4
Now simplify by dividing top and bottom by 2
X= -5/2 or - 2 1/2
“6 sq 3 inches “ ? Explain it briefly I’m trying to understand
