Ince they are equal in absolute value and merely differ in being positve or negative, result in a sum of 0
I think it best to actually do the problem to determine the correct answer.
Clearing out the fractions, I found that
x(x-2) - (x -1) = 2x -5. This results in x=2 and x=3.
However, 2 is not a solution (but is an extraneous solution), because substituting 2 for x in the 2nd term results in div. by zero.
Thus, only the second answer is correct.
IT DOES NOT MATTER YOU WILL NOT BE ABLE TO SOLVE THIS QUESTION
YOU WOULD GET 5x = 2 + 3x^2 AND YOU WOULD STILL NOT BE ABLE TO SOLVE YOU COULD GET 3x^2 = 2 + 5x AND YOU COULD NOT SOLVE.
THE REASON WHY IS BECAUSE YOU HAVE TO HAVE THE SAME X TO ADD THEM OR MINUS THEM< WHICH IN THIS CASE ONE IS REGULAR BUT THE OTHER IS SQUARED. AND ALSO THE TWO NEEDS SOMEONE TO GO WITH< BUT THE IS ONLY ONE OF HIS TYPE SO HE CAN'T.
WELCOME :/
The first thing you want to do is combine like terms
4 + 5x = 12x -10
and make x on one side alone
14 = 7x
divide by 7 to make x alone
2 = x
The answer is 2
Answer:
B
Step-by-step explanation:
Dependent variable: the one being measured
