All categories

3 years ago

12+5x-8=12x-10 Help me solve it step by step

1 answer:

6 0

The first thing you want to do is combine like terms

4 + 5x = 12x -10

and make x on one side alone

14 = 7x

divide by 7 to make x alone

2 = x

The answer is 2

You might be interested in

For which of the following compound inequalities is there no solution?

Bess [88]

Answer:

(a) $6m \le - 36$ and $m + 24 > 20$

Step-by-step explanation:

Required

Which of a to d has no solution

(a) $6m \le - 36$ and $m + 24 > 20$

We have: $m + 24 > 20$

Sole for m

$m >20 - 24$

$m >-4$

$6m \le - 36$

Divide by 6

$m \le -6$

So, we have:

$m \le -6$ and $m >-4$

$m \le -6$ implies that: m = -6,-7,-8,-9.....

$m >-4$ implies that m = -3,-2,-1,0.....

<em>Hence, there is no solution</em>

8 0

2 years ago

Can you think of any 2x2 matrices d for which cd = dc for all 2x2 matrices c? give 2 different examples of such matricesd.

Ksju [112]

For any arbitrary 2x2 matrices $\mathbf C$ and $\mathbf D$ , only one choice of $\mathbf D$ exists to satisfy $\mathbf{CD}=\mathbf{DC}$ , which is the identity matrix.

There is no other matrix that would work unless we place some more restrictions on $\mathbf C$ . One such restriction would be to ensure that $\mathbf C$ is not singular, or its determinant is non-zero. Then this matrix has an inverse, and taking $\mathbf D=\mathbf C^{-1}$ we'd get equality.

6 0

3 years ago

Given that A and B are true and X and Y are false, determine the truth value of the following proposition: ~[(A ⊃ Y) v ~(X ⊃ B)]

Anni [7]

Answer:

The value of the proposition is FALSE

Step-by-step explanation:

~[(A ⊃ Y) v ~(X ⊃ B)] ⋅ [~(A ≡ ~X) v (B ⊃ X)]

Let's start with the smallest part: ~X. The symbol ~ is negation when X is true with the negation is false and vice-versa. In this case, ~X is true (T)

~[(A ⊃ Y) v ~(X ⊃ B)] ⋅ [~(A ≡ T) v (B ⊃ X)]

Now the parts inside parenthesis: (A ⊃ Y),(X ⊃ B),(A ≡ T) and (B ⊃ X). The symbol ⊃ is the conditional and A ⊃ Y is false when Y is false and A is true, in any other case is true. The symbol ≡ is the biconditional and A ≡ Y is true when both A and Y are true or when both are false.

(A ⊃ Y) is False (F)

(X ⊃ B) is True (T)

(A ≡ T) is True (T)

(B ⊃ X) is False (F)

~[(F) v ~(T)] ⋅ [~(T) v (F)]

The two negations inside the brackets must be taken into account:

~[(F) v F] ⋅ [F v (F)]

The symbol left inside the brackets v is the disjunction, and A v Y is false only with both are false. F v (F) is False.

~[F] ⋅ [F]

Again considerating the negation:

T⋅ [F]

Finally, the symbol ⋅ is the conjunction, and A v Y is true only with both are true.

T⋅ [F] is False.

5 0

2 years ago

Please help me with these rotation problem.

FrozenT [24]

Answer:

see below

Step-by-step explanation:

In the attachment, the points are listed in the order given in the problem statement. (They are listed to the right of the "rotation matrix", with x-coordinates above y-coordinates.)

I really don't like to do repetitive calculations, so I try to use a graphing calculator or spreadsheet whenever possible. Angles are measured CCW.

As always, the rotation transformations are ...

180° — (x, y) ⇒ (-x, -y)

270° — (x, y) ⇒ (y, -x)