Evaluate (2 a + b)^2/(3 b - 1) where a = -2 and b = 5:
(2 a + b)^2/(3 b - 1) = (5 - 2×2)^2/(3×5 - 1)
3×5 = 15:
(5 - 2×2)^2/(15 - 1)
| 1 | 5
- | | 1
| 1 | 4:
(5 - 2×2)^2/14
2 (-2) = -4:
(-4 + 5)^2/14
5 - 4 = 1:
1^2/14
1^2 = 1:
Answer: 1/14
I think it’s gonna be 6 adults for every 42 students not really sure so sorry if I got it wrong
I=PRT/100
1. Make R (rate) subject
R/100= I/PT
2. Substitute and calculate
r/100= i/pt
r/100= 40/400 × 1
(<em>4</em><em>0</em><em> </em><em>i</em><em>s</em><em> </em>from 440-400.<em>T</em><em>h</em><em>e</em><em> </em><em>i</em><em>n</em><em>t</em><em>e</em><em>r</em><em>e</em><em>s</em><em>t</em>)
r/100= 0.1
r/100×100= 0.1×100
r=10% (interest rate per year)
To confirm
I=PRT
I= 400×10/100×1
I= $40 (Interest)
Answer: 5 times
Step-by-step explanation:
Let the number of times that he saved $75 be x.
Let the number of times that he saved $150 be y.
Therefore, based on the information given in the question, we can form an equation which will be:
x + y = 8 ...... i
75x + 150y = 825 ....... ii
From equation I,
x + y = 8
y = 8 - x....... iiii
Put equation iii into ii and this will be:
75x + 150y = 825
75x + 150(8 - x) = 825
75x + 1200 - 150x = 825
75x - 150x = 825 - 1200
-75x = -375
x = 375/75
x = 5
He saved $75 5times from his paycheck.
