<span>Based on the problems I have recently done on FLVs with this though, is that if you connect the center of the arcs to the top intersection point, if the angle degrees, and opposite arcs are the same then it is an equilateral triangle.</span>

8 0

3 years ago

a pair of basketball shoes was originally priced at $80, but was marked up 37.5%. what was the retail price of the shoes

Galina-37 [17]

37.5% of $80 = $30
Since it is marked up, you add $30 to the current price.
$80 + $30 = $110.

5 0

3 years ago

PLEASE HHELP!!! Bring the fraction:

Anna35 [415]

Answer:

$\frac{b}{7a^2c} = \frac{5abc^2}{35a^3c^3}$

$\frac{a}{a - 4} = \frac{-a^2 - 4a}{16 -a^2}$

Step-by-step explanation:

Given

$\frac{b}{7a^2c}$

Express the denominator as $35a^3c^3$

To do this, we divide $35a^3c^3$ by the denominator

$\frac{35a^3c^3}{7a^2c} = 5ac^2$

So, the required fraction is:

$\frac{b}{7a^2c} * \frac{5ac^2}{5ac^2}$

$\frac{5abc^2}{35a^3c^3}$

Hence:

$\frac{b}{7a^2c} = \frac{5abc^2}{35a^3c^3}$

Given

$\frac{a}{a - 4}$

Express the denominator as $16 - a^2$

Multiply the fraction a+4/a+4

So, we have:

$\frac{a}{a - 4} * \frac{(a + 4)}{(a + 4)}$

Apply difference of two squares to the denominator

$\frac{a^2 + 4a}{a^2 - 16}$

Take the additive inverse of the numerator and denominator

$\frac{-(a^2 + 4a)}{-(a^2 - 16)}$

$\frac{-a^2 - 4a}{16 -a^2}$

Hence:

$\frac{a}{a - 4} = \frac{-a^2 - 4a}{16 -a^2}$

8 0

2 years ago

If the line passes through the point (0,4) and has a slope of -1, find the solution to the system.

soldier1979 [14.2K]

Answer:

y = - x + 4

Step-by-step explanation:

Use point-slope form: y-k = m(x-h) for point (h,k) with slope m

now just plug and chug:

y-4 = -1(x-0)

y-4 = -x

y= -x+4

not sure about what you meant by "solution." Just gonna assume that you were looking for the equation.

3 0

1 year ago