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3 years ago

Can anyone please help me :)

Mathematics

1 answer:

Dovator [93]3 years ago

7 0

Answer:

40^14 over 4^5 then divide 40 by 4 and 14-5 which would be 10^9

Step-by-step explanation:

i think, im not positive but you multiply the whole numbers and add the exponents then you can simplify the numerator and denominator. but you dont divide the numerator exponets by the 5, you just sutract. if you want i can explain it a lil better in the comments

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PLEASE HELP!!!!!!!!!!!

vaieri [72.5K]

Answer and Step-by-step explanation:

If my calculations are correct,

A. 17b = w

B. 867 = w

C. 3 bottles for 51 fluid ounces of water

For B and C, just plug in the values.

For A, it was 17 ounces for every bottle (b), so that's why it is multiplied together. This is then equal to w, the total volume of water in fluid ounces.

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3 years ago

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Gnesinka [82]

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4 years ago

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Which value (s) of x are solution(s) of the equation below?

Brut [27]

Answer:g

Step-by-step explanation:

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3 years ago

Airline passengers arrive randomly and independently at the passenger-screening facility at a major international airport. The m

marshall27 [118]

Answer:

1. 0.0000454

2. 0.01034

3. 0.0821

4. 0.918

Step-by-step explanation:

Let X be the random variable denoting the number of passengers arriving in a minute. Since the mean arrival rate is given to be 10,

$X \sim Poi(\lambda = 10)$

1. Requires us to compute

$P(X = 0) = e^{-10} \frac{10^0}{0!} = 0.0000454$

2. We need to compute $P(X \leq 3) = P(X =0) + P(X =1) + P(X =2) + P(X =3)$

$P(X =1) = e^{-10} \frac{10^1}{1!} = 0.000454$

$P(X =2) = e^{-10} \frac{10^2}{2!} = 0.00227$

$P(X =3) = e^{-10} \frac{10^3}{3!} = 0.00757$

$P(X \leq 3) =0.0000454+ 0.000454 + 0.00227 + 0.00757 = 0.01034$

3. The expected no. of arrivals in a 15 second period is = $10 \times \frac{1}{4} = 2.5$ . So if Y be the random variable denoting number of passengers arriving in 15 seconds,

$Y \sim Poi(2.5)$

$P(Y=0) = e^{-2.5} \frac{2.5^0}{0!} = 0.0821$

4. Here we use the fact that Y can take values $0,1, \dotsc$ . So, the event that "Y is either 0 or $\geq$ 1" is a sure event ( i.e it has probability 1 ).

$P(Y=0) + P(Y \geq 1) = 1 \implies P(Y \geq 1) = 1 -P(Y=0) = 1 - 0.0821 = 0.918$

3 0

3 years ago

Please help me and give me correct answer

snow_lady [41]

The house is in the coordinate plane is (4.5, -1.5).

Thats all I know, hope that helped for now.

~Sam

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3 years ago