Answer:
4 2/3 ÷ 3 1/3= 1 2/5
Step-by-step explanation:
First, you turn the mixed terms into an improper fraction like this
4 2/3 → 14/3 because when you multiply 4 times 3 equaling 12 then having 2 then adding that you get 14/3.
3 1/3 → 10/3 because when you multiply 3*3=9 then having 1 and adding that you get 10/3.
Then, you do KCF which stands for <u>Keep Change Flip</u> so for this you would do: 14/3 ÷ 10/3 → 14/3 × 3/10
14 × 3 = 42 and 3 × 10= 30
Now being 42/30 this is considered an improper fraction in which you have to transform it into a mixed number like this:
(For this you need to find the greatest common factor)
42/30 → 42 and 30 greatest common factor is 6 because they are divisible and factor of 6.
Now you divide both the denominator and the numerator y 6 like this:
42 ÷ 6= 7
30 ÷ 6= 5
Now we have 7/5, this is still an improper number so we see how many times 7 can go to 5 which is once. So we have 1 as whole number, now we put the reminder as the numenator of the mix fraction keeping 5 as being the denominator.
Overall, We have our answer 1 2/5
I hope this helps :D
Answer:
thanks for the points bye bye for now
Step-by-step explanation:
thanks for the points bye bye for now love u
The answer is A because the “hops” are jumping over two spaces which equals 2/10 simplified to 1/5. and since the number line stops at 2 it’d be 2 and not 1. If you do the keep change flip method for answer option one you get 10.
X=12
Hope this helps
10x-20+6x+8=180º
9514 1404 393
Answer:
23) 35.77 in²
25) 48.19 cm²
Step-by-step explanation:
Use the appropriate area formula with the given information.
__
23) The area of a triangle is given by the formula ...
A = 1/2bh . . . . . base b, height h
A = 1/2(9.8 in)(7.3 in) = 35.77 in²
__
25) The area of a parallelogram is given by the formula ...
A = bh . . . . . . base b, height h
A = (7.9 cm)(6.1 cm) = 48.19 cm²
_____
The <em>height</em> in each figure is <em>measured perpendicular to the base</em>. This tells you that the length 10.6 cm of the diagonal side of the triangle is not relevant to finding the area.
