Let's let x be the number of t-shirts.
So the first company charges $43 plus $9 per shirt. For x shirts, the cost is the base fee plus 9 times x, or

.
The second company charges a $58 fee plus $8 per shift. The cost is

.
Now, we want to find which fee is less when we are buying 20 shirts. We plug in 20 for x.
The first company charges

.
The second company charges

.
The costs are VERY close, but the second company ultimately charges
less.
Answer:
a) yes
b) ( 0.0280 , 0.1720 )
c) No
Step-by-step explanation:
A) Determine if the sample sizes are large enough
where :
ages between ( 18 to 29 )
p1 = 0.48 ,
n1 = 178 , ∴ n1 P1 = 85.44 also n1 ( 1 - p1 ) = 92.56
ages between ( 50 to 64 )
P2 = 0.03 ,
n2 = 427 ∴ n2p2 = 12.81 also n2( 1 -p2 ) = 414.19
<em>since all the values ae above 10 we can conclude that the sample sizes are large enough </em>
<em>answer = yes </em>
<u>B) Estimate the difference in the proportion of adult Americans aged 18 to 29</u>
= ( 0.0280 , 0.1720 )
attached below is the detailed solution
C) zero is not included in the interval
Im pretty sure it's C because
w/7>3
7×(w/7)>(3)×7
w<21
1. First of all arrange the data set in either ascending or descending order.
12, 19, 24, 26, 31, 38, 53. N = 7 (number of data items)
Median position = 1/2(N + 1)th item = 1/2(7 + 1)th item = 1/2(8)th item = 4th item = 26
First quatile = 1/4(N + 1)th item = 1/4(7 + 1)th item = 1/4(8)th item = 2nd item = 19
Third quatile = 3/4(N + 1)th item = 3/4(7 + 1)th item = 3/4(8)th item = 6th item = 38
Interquatile range = Third quartile - first quatile = 38 - 19 = 19