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Anastasy [175]
2 years ago
14

If x = 1 -√2, find the value of ( x -1/x)^3

Mathematics
1 answer:
vivado [14]2 years ago
8 0

Answer:

8

Step-by-step explanation:

  • (x-1/x)³
  • ((1-√2)-1/(1-√2))³
  • 8
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Find the nonpermissible replacement for y in<br> this expression.<br> y + 9<br> y+7
BigorU [14]

Answer:

idk

Step-by-step explanation:

3 0
2 years ago
If f(x)=2x^3-6x^2-16x-20f(x)=2x *3 −6x *2−16x−20 and f(5)=0, then find all of the zeros of f(x)f(x) algebraically.
mihalych1998 [28]

The zeros of the cubic function f(x) = 2x³ - 6x² - 16x - 20 are given as follows:

x = 5, x = -1 + i, x = -1 - i.

<h3>How to obtain the solutions to the equation?</h3>

The equation is defined by the rule presented as follows:

f(x) = 2x³ - 6x² - 16x - 20.

One solution for the equation is given as follows:

x = 5.

Because f(5) = 0.

Then (x - 5) is a linear factor of the function f(x), which can be written as follows:

2x³ - 6x² - 16x - 20 = (ax² + bx + c)(x - 5).

This is because the product of a linear function and a quadratic function results in a cubic function.

Now we expand the right side to begin finding the coefficients of the quadratic function that we are going to solve to find the remaining zeros:

2x³ - 6x² - 16x - 20 =  = ax³ + (b - 5a)x² + (c - 5b)x - 5c.

Then these coefficients are obtained comparing the left and the right side of the equality as follows:

  • a = 2.
  • -5c = -20 -> c = 4.
  • b = -6 + 5a = 4.

Hence the equation is:

2x² + 4x + 4.

Using a quadratic equation calculator, the remaining zeros are given as follows:

  • x = -1 + i.
  • x = -1 - i.

More can be learned about the solutions of an equation at brainly.com/question/25896797

#SPJ1

8 0
10 months ago
A rental car cost $60 plus an additional $0.15 per mile. What is the cost of renting a car for one day and driving it 65 miles.
ICE Princess25 [194]

Answer:

$69.75

Step-by-step explanation:

60+0.15x is your expression.

Now, plug in 65 miles for x, as that is the changing value.

60+(0.15*65)

60+9.75

$69.75

7 0
3 years ago
Find the discriminant and determine the nature of the roots to the quadratic equation
Katen [24]
№17
x^{2} +6x-7=0 \\ D=6 ^{2} -4*(-7)=36+28=64=8 ^{2}  \\  \\  x_{1} = \frac{-6+8}{2} =1 \\  \\  x_{2} = \frac{-6-8}{2} =-7
Answer: x₁ = 1
               x₂ = - 7

№18
2 x^{2} -3x+4=3 \\ 2 x^{2} -3x+4-3=0 \\ 2 x^{2} -3x+1=0 \\  \\ D= -3 ^{2} -4*2=9-8=1 \\  \\  x_{1} = \frac{3+1}{2*2} = \frac{4}{4} =1 \\  \\  x_{2} = \frac{3-1}{2*2} = \frac{2}{4} =0.5
Answer: x₁ = 1
               x₂ = 0,5.

№19
2 x^{2} -4x-5=0 \\  D=-4 ^{2} -4*2*(-5)=16+40=56 \\  \\  x_{1}= \frac{4+ \sqrt{56} }{2*2}  = \frac{4}{4} + \sqrt{ \frac{56}{16} } =1+ \sqrt{3.5}  \\  \\  x_{2} = \frac{4- \sqrt{56} }{2*2} = \frac{4}{4} -  \sqrt{ \frac{56}{16} } =1- \sqrt{3.5} &#10;
Answer: x₁ = 1 + √3.5
               x₂ = 1 - √3.5

3 0
3 years ago
Please I need help badly and quickly, pls do not answer if you just want the points. I need an accurate answer for this. Cheers
natita [175]

Answer

Q11 is 50,3

Q12, 23,19

Step-by-step explanation:

7 0
2 years ago
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