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alekssr [168]
3 years ago
6

What is the value of x in the equation 6(х + 1) — 5х = 8 + 2(x — 1)?

Mathematics
1 answer:
Licemer1 [7]3 years ago
6 0

Multiply the first bracket by 6.

Multiply the second bracket by 8

6(x+1)-5x= 8+2(x-1)

6(x)+6(1)-5x= 8+2(x)+2(-1)

6x+6-5x= 8+2x-2

6x-5x+6= 8-2+2x

x+6= 6+2x

Move +2x to the other side. Sign changes from +2x to -2x.

x-2x+6= 6+2x-2x

-x+6= 6

Move +6 to the other side. Sign changes from +6 to -6.

-x+6-6= 6-6

-x=0

Multiply by -1 for -x and 0

-x(-1)= 0(-1)

x= 0

Answer: x= 0

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Without calculating, which has a bigger volume. A cube that has a length, width, and height of 18 m. Or a sphere with a radius o
Evgesh-ka [11]

Weird. A period appears above this... huh.

Answer:

[Th]e cube has a greater value.

Step-by-step explanation:

What the word problem really wants us to get [is ]the question of 'Which is greater, A=6a^2 when 'a' [is] 18 or A=4\pir^2 when r = 9? And here's how to solve that.

Starting with the[ c]ube we have A=6a^2. A bit t[o]o simple, right?

A=6(18)^2 Substitute numbers.

A=6(324) Solve ex[p]onents.

A=1944 Mult[i]ply.

So w[e] know that the cube is 1944 meters cube[d ] in area. But what about the more [f]ormidable sphere? Fo[r] it we need a slightly m[o]re co[m]plicated formula, A=4\pir^2. However, instead of using the real pi I will be rounding to 3.14, since we have no calculator so anything more would take way too long and fry your[ bra]in.

A=4(3.14)(9)^2 Subst[i]tute numbers.

A=4(3.14)(81) Solve expone[n]ts.

A=12.56(81) Multip[ly].

A=1017.36 Multiply again[.]

Now, since I'm sure all of us can count, we know that 1944 is greater than 1017.36. Or in other words, the cube is bigger than the sphere.

And PLEASE don't copy this guys. Make your own iteration. Change it up!

3 0
3 years ago
Which best summarizes the Pythagorean Theorem?
bezimeni [28]

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the bottom right one

Step-by-step explanation:

3 0
2 years ago
In an inductive generalization, in order to achieve an error margin of plus or minus 3 percentage points at a confidence level o
ANTONII [103]
Let n =  required random sample size.

Assume that the population standard deviation is known as σ.
Let m =  sample mean.
At the 95% confidence level, the expected range is
(m - k(σ/√n), m + k(σ/√n))
where k = 1.96.

Therefore the error margin is 1.96(σ/√n).
Because the error margin is specified as 3% or 0.03, therefore
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n = 128.05σ²

This means that the sample size is about 128 times the population variance.

Answer:
Smallest sample size = 128.05σ², where σ = population standard deviation.
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