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arsen [322]
2 years ago
5

Find all numbers whose absolute value is 5.

Mathematics
1 answer:
melamori03 [73]2 years ago
3 0

Answer:

5 , -5

Step-by-step explanation:

c'mon this is easy. the absolute value of a number is that numbers distance away from zero on the number line. 5 and -5 are the only numbers that are five intergers away from zero.

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(3x5)-1 expression word
pshichka [43]

Answer:

Subtract the result of three times five with 1.

Step-by-step explanation:

(3 \times 5)-1

15-1

14

Subtract the result of three times five with 1.

4 0
3 years ago
Which picture has a line of symmetry
Arturiano [62]
Add the picture pls
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3 years ago
A manager of a grocery store wants to determine if consumers are spending more than the national average. The national average i
strojnjashka [21]

The valid conclusions for the manager based on the considered test is given by: Option

<h3>When do we perform one sample z-test?</h3>

One sample z-test is performed if the sample size is large enough (n  > 30) and we want to know if the sample comes from the specific population.

For this case, we're specified that:

  • Population mean = \mu = $150
  • Population standard deviation = \sigma = $30.20
  • Sample mean = \overline{x} = $160
  • Sample size = n = 40 > 30
  • Level of significance = \alpha = 2.5% = 0.025
  • We want to determine if the average customer spends more in his store than the national average.

Forming hypotheses:

  • Null Hypothesis: Nullifies what we're trying to determine. Assumes that the average customer doesn't spend more in the store than the national average. Symbolically, we get: H_0: \mu_0 \leq \mu = 150
  • Alternate hypothesis: Assumes that customer spends more in his store than the national average. Symbolically H_1: \mu_0 > \mu = 150

where \mu_0 is the hypothesized population mean of the money his customer spends in his store.

The z-test statistic we get is:

z = \dfrac{\overline{x} - \mu_0}{\sigma/\sqrt{n}} = \dfrac{160 - 150}{30.20/\sqrt{40}} \approx 2.094

The test is single tailed, (right tailed).

The critical value of z at level of significance 0.025 is 1.96

Since we've got 2.904 > 1.96, so we reject the null hypothesis.

(as for right tailed test, we reject null hypothesis if the test statistic is > critical value).

Thus, we accept the alternate hypothesis that customer spends more in his store than the national average.

Learn more about one-sample z-test here:

brainly.com/question/21477856

3 0
1 year ago
Read 2 more answers
Find the 87th term of this sequence: 157, 150, 143, ...
nirvana33 [79]

Answer:

<h3>                 \bold{a_{87}=-445}</h3>

Step-by-step explanation:

a_1=157\\a_2=150\\\\d=150-157=-7\\\\a_n=a_1+d(n-1)\\\\a_{87}=157+(-7)(87-1)=157-7\cdot86=-445

7 0
3 years ago
The variability at each feeder is 3.168. The difference between the median number of hummingbirds spotted per day at each feeder
vesna_86 [32]
The answer is 4 has to be
3 0
3 years ago
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