Answer:
Green and Blue ribbon
Step-by-step explanation:
Given
They collect
Red Ribbon = ½ mile
Green Ribbon = ⅛ mile
Blue Ribbon = ¼ mile
To find?
Which colors of ribbons will be collected at the ¾ mile mark.
The interpretation of the question is to test which of the above fractions can divide ¾ without a remainder; in other words, multiples of ¾.
Testing each fraction.
Red Ribbon = ½
¾ ÷ ½
= ¾ * 2
= 3/2
= 1.5 or 1 Remainder 1
This is not an exact multiple of ¾. So, the red ribbon won't be passed here.
Green Ribbon = ⅛
¾ ÷ ⅛
= ¾ * 8
= 24/8
= 3
This is an exact multiple of ¾. So, the green ribbon will be collected.
Testing the last ribbon
Blue = ¼
¾ ÷ ¼
= ¾ * 4
= 3
This is an exact multiple of ¾. So, the blue ribbon will be collected.
Hence, the green and blue ribbons will be collected at ¾ mile mark
Is 1/3 a fraction or division?
If division then the answer would be s= 1/27 (a fraction)
Answer:
There are 5,827,360 different outcomes.
Step-by-step explanation:
Fundamental counting principle:
States that if there are p ways to do a thing, and q ways to do another thing, and these two things are independent, there are p*q ways to do both things.
In each party:
The order in which the people are selected is important(first is chair, second vice chair), which means that the permutations formula is used to solve this question.
Permutations formula:
The number of possible permutations of x elements from a set of n elements is given by the following formula:

Reds:
Two from a set of 44. So

Blues:
Two from a set of 56. So

How many different outcomes are there for the chair and vice chair elections of both parties?
Considering both, by the fundamental counting principle:
1892*3080 = 5827360
There are 5,827,360 different outcomes.
The key to solving this problem is drawing a rectangle outside the figure and subtracting the reas of the triangles formed from the are of the rectangle. You can look at the attched image if you want a visual.So first let's find the area of the rectangle, the length is 11 and the width is 5 so the area is 55. Now let's find the area of the trinagles. Triangle 1 has sides of 4 and 3 so the area is 6. Triangle 2 has sides of 5 and 5 so the area is 25/2. Triangle 3 has sides of 2 and 5 so the area is 5. Now let's add the area of the triangles up to get 47/2. Now let's subtract 47/2 from 55 to get the area of the figure which is *drumroll*...63/2. that's all.
The answer is x=14.......