All categories

2 years ago

Please view the two images below and help me asap!!!!!!!!! for a brainlist ;))

Mathematics

1 answer:

love history [14]2 years ago

3 0

Answer:

rate of exchange is -2/-2

You might be interested in

7/8 = y/11 solve for y

olasank [31]

7/8 = y/11

so multiply 11 to both sides of the equation

so now its (7*11)/8= y

y=77/8

if decimal then 9.625

hope that helps

5 0

3 years ago

Read 2 more answers

Buddie is filing his federal income tax

Alexxandr [17]

Answer: ????

Step-by-step explanation:

CAN YOU EXPLAIN WHAT THE QUESTION IS?

IS THERE ANY BACKGROUND INFORMATION ON THIS QUESTION?

DO YOU KNOW THE ANSWER?

WHERE DID THE PROBLEM COME FROM?

WITHOUT THE INFORMATION, WE ARE NOT ABLE TO ANSWER THE QUESTION.

4 0

3 years ago

Read 2 more answers

14. Find the solution of the initial value problem y′′ + y = F(t), y(0) = 0, y′(0) = 0, where F(t) = ⎧⎪⎨⎪⎩ At, 0≤ t ≤ ????, A(2?

Vinvika [58]

Yxgxgggffggyygfccccgyu

3 0

2 years ago

Cos(−θ)=√3/3, sinθ<0

Delicious77 [7]

Answer:

$\sin\theta=-\frac{\sqrt{6}}{3}$

Step-by-step explanation:

The given trigonometric equation is $\cos(-\theta)=\frac{\sqrt{3} }{3}$ .

We can either use the Pythagorean identity or the right angle triangle to solve for $\sin\theta$ .

According to the Pythagorean identity,

$\cos^2\theta+\sin^2\theta=1$

Recall that, the cosine function is an even function, therefore

$\cos(-\theta)=\cos(\theta)$

$\Rightarrow \cos(\theta)=\frac{\sqrt{3} }{3}$ .

We substitute this value in to the above Pythagorean identity to get;

$(\frac{\sqrt{3}}{3})^2+\sin^2\theta=1$

$\Rightarrow \frac{3}{9}+\sin^2\theta=1$

$\Rightarrow \sin^2\theta=1-\frac{3}{9}$

$\Rightarrow \sin^2\theta=\frac{6}{9}$

$\Rightarrow \sin\theta=\pm \sqrt{\frac{6}{9}}$

$\Rightarrow \sin\theta=\pm \frac{\sqrt{6}}{3}$

But we were given that,

$\sin\theta\:$ , so we choose the negative value.

$\Rightarrow \sin\theta=-\frac{\sqrt{6}}{3}$

The correct answer is B

7 0

3 years ago

Need help with number 5

tangare [24]

Answer:

(3) y = 4x

Step-by-step explanation:

In order for the equation not to change, the point (0, 0) must be on the original line and so on the line after dilation. The only equation with (0, 0) as a point on the line is y=4x.

Dilation about the origin moves all points away from the origin some multiple of their distance from the origin. If a point is on the origin, it doesn't move. We call that point the "invariant" point of the transformation. For the equation of the line not to change, the invariant point must be on the line to start with.

8 0

2 years ago