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Alex
3 years ago
5

Which line shows theINITIAL error in volume work?

Mathematics
1 answer:
aliina [53]3 years ago
7 0

In step 2, V = \frac{4}{3}(3.14)(37.5) show the error in volume work.

Solution:

Given data:

The steps shows it is sphere.

Radius of the sphere = 12.5

The value of π = 3.14

Volume of the sphere = \frac{4}{3} \pi r^3

Step 1:

$V=\frac{4}{3} (3.14)(12.5)^3

$V=\frac{4}{3} (3.14)(12.5)(12.5)(12.5)

Step 2:

$V=\frac{4}{3} (3.14)(1953.125)

Step 3:

$V=\frac{4}{3} (6132.81)

Step 4:

V = 8177.08 cubic units

This is the correct solution.

But in the given options, in step 2, 12.5 is multiplied by 3.

That is not the correct step. You have to do 12.5 × 12.5 × 12.5.

Hence in step 2, V = \frac{4}{3}(3.14)(37.5) show the error in volume work.

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Step-by-step explanation:

Since we are given two equations, this equations will be solved simultaneously to get a² and b²

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From 1, a(a² - 3b²) = 47...3

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Adding 3 and 4, we have;

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Taking the difference we have

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