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Alex
3 years ago
5

Which line shows theINITIAL error in volume work?

Mathematics
1 answer:
aliina [53]3 years ago
7 0

In step 2, V = \frac{4}{3}(3.14)(37.5) show the error in volume work.

Solution:

Given data:

The steps shows it is sphere.

Radius of the sphere = 12.5

The value of π = 3.14

Volume of the sphere = \frac{4}{3} \pi r^3

Step 1:

$V=\frac{4}{3} (3.14)(12.5)^3

$V=\frac{4}{3} (3.14)(12.5)(12.5)(12.5)

Step 2:

$V=\frac{4}{3} (3.14)(1953.125)

Step 3:

$V=\frac{4}{3} (6132.81)

Step 4:

V = 8177.08 cubic units

This is the correct solution.

But in the given options, in step 2, 12.5 is multiplied by 3.

That is not the correct step. You have to do 12.5 × 12.5 × 12.5.

Hence in step 2, V = \frac{4}{3}(3.14)(37.5) show the error in volume work.

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If he made a loss of 15%, then it means that selling price is 85% of the cost price.

If the cost price is x, then we have;

0.85x = 595

x = 595/0.85

x = $700

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(-3-(-1))/(-1-4)= 2/5

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Please help.<br> also median is 3
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a. the median is 2

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3 years ago
A manager at an amusement park wants to know how popular the park's biggest roller coaster is. She counts the number of people w
valkas [14]

Answer: minimum = 0.5

maximum = 9.0

first quartile = 3

median = 5.5

third quartile = 7.5

Step-by-step explanation:

The histogram is shown below and used to obtain the various information

Time (hour) (X)     No of People (F)       FX

0.5                             19                            9.5  -- minimum = 0.5    

1                                20                            20

1.5                              21                             31.5

2                                 22                            44

2.5                              23                            57.5

3                                 24                             72 ----first quartile = 3

3.5                              26                             91

4                                 27                              108

4.5                             28                               126

5                                29                                145

5.5                            30                               165 --median/ inter quartile =5.5

6                               31                                186

6.5                           32                                208

7                               33                                 231

7.5                            34                                255-- third quartile = 7.5

8                               35                                280

8.5                            36                               306        

9                                37                              333 --- maximum = 9

T=85.5                   T = 507                      T=  2666.82     T = TOTAL

mean = sumFX/sumF  =   2666.82/507 = 5.26

Median = middle number = inter quartile =5.5 (507/2 = 253.5 = 254 and  add the frequency from top = 19+20+21+ 22+ 23+ 24+26+ 27+ 28+ 29 =269

and 254  close to 269 that is the frequency is within the range and corresponds to 5.5

first quartile = 1/4 *507 = 126.75 = 127 ( add the frequency from top= 19+20+21+ 22+ 23+ 24= 129 and 127 is close to 129)

third quartile = 3/4 * 507 = 380.25 ( add the frequency from top = 19+20+21+ 22+ 23+ 24+26+ 27+ 28+ 29+ 30+ 31+32+ 33+ 34 = 399 and 380 is close to 399 so the third quartile is 7.5

minimum is the one with lowest frequency = 0.5 at 19

maximum  or mode is the one with highest frequency = 9 at 37

4 0
3 years ago
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