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kipiarov [429]
3 years ago
15

What is the reason for the step taken from the proof below?

Mathematics
1 answer:
seraphim [82]3 years ago
7 0

Answer:

Option (4)

Step-by-step explanation:

Vertical angles theorem;

"Two vertically opposite angles formed by the intersection of two straight lines are congruent"

By this theorem,

If ∠1 and ∠2 are the vertical angles                            Given

∠1 ≅ ∠2                                                                Vertical angles theorem

Therefore, Option (4) is the correct option.

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What are the x-intercept and y-intercept of the graph of y=13x−6 ?
gtnhenbr [62]
To find the x-int., let y = 0 and solve for x:  13x = 6, so x = 6/13:  (6/13, 0)

To find the y-int., let x =0 and read off the y-int:  (0, -6)
7 0
3 years ago
Read 2 more answers
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maw [93]

Answer:

<u>x = 5</u>

Step-by-step explanation:

See attached image.

8 0
2 years ago
Which equation shows the inverse property of multiplication?
serious [3.7K]

Answer:

C

Step-by-step explanation:

The options are:

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<em>B. -8 + (-3) = -3 + (-8) </em>

<em>C. 2 </em>×<em> 1/2 = 1 </em>

<em>D. 8/5 + 0 = 8/5</em>

<em />

The inverse property of multiplication states that the product of a number and its inverse is one.

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8 0
3 years ago
Find all of the points of the form (x −1) which are 4 unit from the point (3,2)
Bond [772]

Answer:

(3+2\sqrt{2},2+2\sqrt{2}),(3-2\sqrt{2},2-2\sqrt{2})

Step-by-step explanation:

Points\ are\ of\ the\ form\ (x,x-1)\\\\Distance\ of\ these\ points\ from\ (3,2)=4\\\\\sqrt{(x-3)^2+(x-3)^2}=4\\\\\sqrt{(x-3)^2+(x-1-2)^2}=4\\\\\sqrt{2(x-3)^2}=4\\\\2(x-3)^2=16\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ square\ both\ the\ sides\\\\(x-3)^2=\frac{16}{2}\\\\(x-3)^2=8\\\\(x-3)=\pm 2\sqrt{2}\ \ \ \ \ \ \ \ \ \ \ square\ root\ both\ the\ sides\\\\x=3\pm 2\sqrt{2}\\\\When\ x=3+2\sqrt{2}\ \ \Rightarrow x-1=3+2\sqrt{2}-1=2+2\sqrt{2}\\\\When\ x=3-2\sqrt{2}\ \ \Rightarrow x-1=3-2\sqrt{2}-1=2-2\sqrt{2}

4 0
3 years ago
Please help me ASAP
ANTONII [103]

Answer:

Step-by-step explanation:

24 foot

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