GIRLL I DONT SEE YOUR PIC
3(a + b) and 3a + b - NOT EQUIVALENT because
3(a + b) = 3a + 3b
<em>used distributive property a(b + c) = ab + ac</em>
4(x + 2y) and 8y + 4x - EQUIVALENT because
4(x + 2y) = (4)(x) + (4)(2y) = 4x + 8y = 8y + 4x
<em>used distributive property a(b + c) = ab + ac</em>
<em>and commutative property a + b = b + a</em>
Answer:
at least 81 times. playing 80 times would mean you played exactly what it's worth, 7*80=560, so playing 81 times means you pocket a difference of 7 dollars. if you're going to be playing at least 81 times yearly, go for the membership..
Answer: If you need to find the length of the hypotenuse of a right triangle, you can use the Pythagorean theorem if you know the length of the other two sides. Square the length of the 2 sides, called a and b, then add them together. Take the square root of the result to get the hypotenuse
<span>Say the code only needed to be one number long. Going from 0-9, there are ten digits. Therefore, there are ten unique codes.
Now say the code has to be two numbers long. There are ten possibilities
for the first digit, 0-9. But the second digit only has nine
possibilities, since each number has to be different. (The first number
might be 0, so the second can only go from 1-9) For each of the first
ten possibilities, there are nine possibilities for the second. We
multiply those two numbers together, 10 * 9, and we get 90.
Now we just extend the logic. The third number only has eight
possibilities, while the fourth number only has seven. 10 * 9 * 8 * 7 =
5040 possible codes. I hope this helped! has a great day! :)</span>
