Answer:
6 plus 4 i times the square root of 5
Step-by-step explanation:
The given statement can be written as:
6+√-80
To solve √-80 re-write -80 as -1 * 80
Now √-80 =√-1 * 80
Now we can write it as:
6+ √-1 * √80
We know that √-1 = i
Thus it becomes:
6+ i√80
Now find the square root of 80
80 does not have a perfect square root
Its square root can be found as 80 = 4*4*5
Then,
6+i√4*4*5
Notice that 4 makes a pair.. So we will write it outside the square root
6+1*4√5
We will write it as:
6+4i√5
Thus the correct option is 6 plus 4 i times the square root of 5....
Answer:
Step-by-step explanation:
First let's re-write the equation:
f(x) = 3x² - 5x + 4
If f(-2). then we can re-write the equation as:
f(-2) = 3(-2)² - 5(-2) + 4
We must solve for exponent first: (-2)² = 4
f(-2) = 3(4) - 5(-2) + 4
Then solve for multiplication:
f(-2) = 12 + 10 + 4
Finally addition:
f(-2) = 26
that means that in a function, if X = -2, then F is equal to 26
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