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Oksi-84 [34.3K]
3 years ago
9

Multiple Choice!!! A school bought a special type of lock for all student lockers. Every student had to create his or her own pa

ss code made up of 4 different numbers from 0-9. How many different pass codes are possible?
A)6,561
B)262,144
C)5,040
D)9

Thank you for your help! :)
Mathematics
1 answer:
Elina [12.6K]3 years ago
8 0
<span>Say the code only needed to be one number long. Going from 0-9, there are ten digits. Therefore, there are ten unique codes.

Now say the code has to be two numbers long. There are ten possibilities for the first digit, 0-9. But the second digit only has nine possibilities, since each number has to be different. (The first number might be 0, so the second can only go from 1-9) For each of the first ten possibilities, there are nine possibilities for the second. We multiply those two numbers together, 10 * 9, and we get 90.

Now we just extend the logic. The third number only has eight possibilities, while the fourth number only has seven. 10 * 9 * 8 * 7 = 5040 possible codes. I hope this helped! has a great day! :)</span>
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