Answer: the maximum of three
Step-by-step explanation: each number has 2 significant figures. so 10.85 has four significant figures and must be rounded to 11 so it can have a maximum of three
15.23*3.6=54.83
Answer:
f(x)=(2x-7)^7(x+3)^4
When y=0, (2x-7)^7=0 and x=3.5 OR
(x+3)^4=0, and x=-3
Look at x=h or f(2)
That is 96-56-44+2 and it is not equal to 0. (x-2) is not a factor.
x^3-5x^2+6x-30
after trying 1,2, and 3, I tried 5
5/1===-5===6===-30
==1===0====6====30
(x^2-6) with no remainder
the factors are (x-5)(x^2+6)
the zeroes are 5, +/- i sqrt (6). Only one real 0.
hope this helps let me know in the comments if i'm wrong
Answer:
The answer to your question is There were sold 166 adult tickets and 294
children tickets.
Step-by-step explanation:
Data
Total number of seats = 460
cost for adults = a = $52
cost for children = c = $26
Total cost = $16276
Process
1.- Write equations to solve this problem
a + c = 460 Equation l
52a + 26c = 16276 Equation ll
2.- Solve the system of equation by substitution.
-Solve equation l for a
a = 460 - c
-Substitute a in equation ll
52(460 - c) + 26c = 16276
-Expand
23920 - 52c + 26c = 16276
-Simplify
-26c = 16276 - 23920
-26c = -7644
c= -7644/-26
c = 294
3.- Find a
a = 460 - 294
a = 166
