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3 years ago

How many grams of a 10% cream must be mixed with 2% cream to prepare 60 grams of a 5% cream?

Mathematics

1 answer:

Blizzard [7]3 years ago

3 0

Answer:

22.5 grams of 10% cream is mixed with 37.5 grams of 2 % cream to prepare 60 grams of 5% cream.

Step-by-step explanation:

Let x grams of 10% cream is mixed with y grams of 2 % cream to prepare 60 grams of 5% cream.

So, x + y = 60 ............ (1) and

$x\times \frac{10}{100} + y \times \frac{2}{100} = 60 \times \frac{5}{100}$

⇒ 10x + 2y = 300

⇒ 5x + y = 150 ............ (2)

Now, solving equations (1) and (2) we get,

4x = 150 - 60 = 90

⇒ x = 22.5 grams

So, y = 60 - x = 37.5 grams. (Answer)

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3 years ago

A tank's length is 3 feet longer than its width. The height is 1 foot less than the width. The volume of the tank is 160 cubic f

Ivanshal [37]

Answer:

The width of the tank is 5 feet.

Step-by-step explanation:

Given:

A tank's length is 3 feet longer than its width.

The height is 1 foot less than the width.

The volume of the tank is 160 cubic feet.

Now, to find the width of the tank.

Let the width of the tank be $x.$

So, length is $x+3.$

And, height is $x-1.$

The volume of tank = 160 cubic feet.

Now, to get the width we put formula:

Volume = length × width × height.

$160=(x+3)\times x\times (x-1)$

$160 =x(x^2-x+3x-3)$

$160=x(x^2+2x-3)$

$160=x^3+2x^2-3x$

Subtracting both sides by 160 we get:

$0=x^3+2x^2-3x-160$

$x^3+2x^2-3x-160=0$

Now, on solving the equation we get:

$x=5.$

The width = 5 feet.

Therefore, the width of the tank is 5 feet.

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4 years ago

Graph y=5^x and 7=log(sub)5x

umka2103 [35]

Domain of y = 5^x is the set of all real numbers Range of y = 5^x is the set of all real numbers y such that y > 0 In interval

notation the domain and range are... Domain: (−∞,∞) Range: (0,∞)

y=5^x and x=0 then y=1

which would mean the y-intercept is 1

The point would be (0,1)

were y= 0

6 0

3 years ago

TIMING THE CAR

kenny6666 [7]

We can define the speed as the quotient between the distance moved, and the time it takes to move that distance, so we have:

speed = Distance/Time.

Now we can rewrite this as:

Distance = Speed*Time.

We will find that the speed of the car was 21 mi/h.

Here the information given is:

Mr. Pipkins speed is: S = 3.5 mi/h

The car needed 27 "steps" to reach the corner.

Mr. Pipkins needed 27 + 135 = 162 "steps" to reach the same corner.

Because the number of steps is related to time and distance, the ratio between the number of steps should be the same as the ratio between the speeds:

162/27 = 6

(Pipkins needed 6 tomes more steps than the car, so the car moves 6 times faster than Pipkins)

This means that the speed of the car is 6 times larger than the speed of Mr. Pipkins.

Then the speed of the car is:

S' = 6*(3.5 mi/h) = 21 mi/h.

If you want to learn more, you can read:

brainly.com/question/24594539

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3 years ago

When is it safe for you to place a construction load on a concrete structure

Mariana [72]

I dunno u would hav to work as a construction worker to find that out

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4 years ago