Answer:
Ok, the domain is the set of values that we can input in a function.
In this case, we have:
y = Ix - 6I + 3.
Notice that there is no restriction here, x can actually take any value, then the domain will be the set of all real numbers.
The correct domain is x, x ∈ R
Now, if we had (for example) something like:
y = Ix - 6I < 3
Now we have a restriction in the domain because we can not have y equal or larger than 3.
To find the domain, we can break the absolute value:
Ix - 6I < 3
is equivalent to:
-3 < x - 6 < 3
now let's add 6 in each side.
-3 + 6 < x - 6 + 6 < 3 + 6
3 < x < 9
That will be the domain in that case.
Answer:
z=( -2 , 5/3) can you speak English
The initial statement is: QS = SU (1)
QR = TU (2)
We have to probe that: RS = ST
Take the expression (1): QS = SU
We multiply both sides by R (QS)R = (SU)R
But (QS)R = S(QR) Then: S(QR) = (SU)R (3)
From the expression (2): QR = TU. Then, substituting it in to expression (3):
S(TU) = (SU)R (4)
But S(TU) = (ST)U and (SU)R = (RS)U
Then, the expression (4) can be re-written as:
(ST)U = (RS)U
Eliminating U from both sides you have: (ST) = (RS) The proof is done.
Answer:
(a) $3800
(b) (a) -- April to May
Step-by-step explanation:
<h3>(a)</h3>
The least amount is found at the lowest point on the graph. That point is in May. It is on the line between 3700 and 3900, so the amount is $3800.
The least donation amount is a month is $3800.
__
<h3>(b)</h3>
The greatest month-to-month decrease is found where the line on the graph has the steepest negative slope. There are two segments with negative slope:
- April - May (decrease of $500)
- June - July (decrease of $100)
The decrease from April to May is by far the largest of these two decreases.
The greatest decrease occurred April to May.
The Awnser would be 20.6 rounded up to 21. The final Awnser is 21
