Q1. A computer program is written to produce a number from 1 to 25 at random.

What is the area of this composite figure?

snow_lady [41]

Answer:

D.) 100 feet squared

Step-by-step explanation:

10 X 6=60

10 X 4=40

60+40=100

4 0

3 years ago

Read 2 more answers

A student measures the diameter of a small cylindrical object and gets the following readings: 4.32, 4.35, 4.31, 4.36, 4.37, 4.3

Keith_Richards [23]

Answer:

The average of the diameter readings is 4.34 cm.

Step-by-step explanation:

We are given the following data set(cm):

4.32, 4.35, 4.31, 4.36, 4.37, 4.34

Formula:

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{26.05}{6} = 4.34167 \approx 4.34$

Thus, the average of the diameter readings is 4.34 cm.

8 0

4 years ago

Find slope of a line using points (2,0) and (4,3)

Lilit [14]

The slope of the line would be 3/2 because the slope formula would be y2-y1/x2-x1 so 3-0=3 and 4-2=2 so 3/2

Hope this helps

Have a great day/night

Feel free to ask any questions

4 0

3 years ago

Practice

viva [34]

Answer:

B.

Step-by-step explanation:

x = small box

(small box + 5 ounces) = large box.

B shows:

x + (x + 5) = 27

Small box + (small box + 5 ounces) = 27 ounces.

Small box + large box = 27 ounces.

————————————————————

Why A and C are incorrect.

A describes:

x + 5x = 27

Small box + 5 multiplied by small box = 27

(5 multiplied by small box is equivalent to 5 small boxes.)

Small box + 5 small boxes = 27

C describes:

x + 5 = 27

small box + 5 ounces = 27

Large box = 27

(We know that a small box + 5 ounces is a large box)

7 0

3 years ago

Unfortunately, arsenic occurs naturally in some ground water†. A mean arsenic level of μ = 8.0 parts per billion (ppb) is consid

riadik2000 [5.3K]

Answer:

$t=\frac{7.2-8}{\frac{2.1}{\sqrt{41}}}=-2.439$

$p_v =P(t_{(40)}$

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and the true mean is lower than 8 ppb at 1% of signficance. We need to be careful with this interpretation since the p value is near to the significance level.

Step-by-step explanation:

Data given and notation

$\bar X=7.2$ represent the mean height for the sample

$s=2.1/tex] represent the sample standard deviation [tex]n=41$ sample size

$\mu_o =8$ represent the value that we want to test

$\alpha=0.01$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the true mean is less than 8, the system of hypothesis would be:

Null hypothesis: $\mu \geq 8$

Alternative hypothesis: $\mu < 8$

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{7.2-8}{\frac{2.1}{\sqrt{41}}}=-2.439$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=41-1=40$

Since is a one side test the p value would be:

$p_v =P(t_{(40)}$

Conclusion

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and the true mean is lower than 8 ppb at 1% of signficance. We need to be careful with this interpretation since the p value is near to the significance level.

4 0

4 years ago