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Shtirlitz [24]
2 years ago
15

Q1. A computer program is written to produce a number from 1 to 25 at random.

Mathematics
1 answer:
Oduvanchick [21]2 years ago
5 0

Answer:

C because I did this problem

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Devin's DVD case has 3 rows of slots, but 5 slots are broken.If x equals the number of slots in a row explain how the expression
Paul [167]

Answer:

The total number of unbroken / working slots

Step-by-step explanation:

Given that Devin's DVD case has 3 rows of slots, but 5 slots are broken

Also given that the number of slots in a row is x

1 row has x slots

3 rows has y slots

on cross multiplication we get y = 3x

ie there are a total of 3x slots in the 3 rows

Given that out of these 3x slots 5 . of the slots are broken

Therefore the total number of working slots = total number of slots - number of slots which are broken

total number of working slots are = 3x - 5

Therefore the given expression is the number of working / good slots

6 0
3 years ago
Sketch the points (0,5,2),(4,0,-1),(2,4,6) and(1,-1,2) o a single set of coordinate axes?
nordsb [41]

Explanation:

As points have three coordinates i.e. x, y and z hence the sketch of the given four points is drawn in 3D shape and for that picture is attached here with this answer.

Points are given in the format as below

(value of x-coordinate , value of y-coordinate , value of z-coordinate)

In the attachment:

Point A = (0,5,2) (in blue color)

Point B = (4,0,-1) (in purple color)

Point C = (2,4,6) (in orange color)

Point D = (1,-1,2) (in black color)

7 0
2 years ago
In a set of 25 aluminum castings, four castings are defective (D), and the remaining twenty-one are good (G). A quality control
lianna [129]

Answer:

The sample space for selecting the group to test contains <u>2,300</u> elementary events.

Step-by-step explanation:

There are a total of <em>N</em> = 25 aluminum castings.

Of these 25 aluminum castings, <em>n</em>₁ = 4 castings are defective (D) and <em>n</em>₂ = 21 are good (G).

It is provided that a quality control inspector randomly selects three of the twenty-five castings without replacement to test.

In mathematics, the procedure to select k items from n distinct items, without replacement, is known as combinations.

The formula to compute the combinations of k items from n is given by the formula:

{n\choose k}=\frac{n!}{k!(n-k)!}

Compute the number of samples that are possible as follows:

{25\choose 3}=\frac{25!}{3!\times (25-3)!}

      =\frac{25\times 24\times 23\times 22!}{3!\times 22!}\\\\=\frac{25\times 24\times 23}{3\times 2\times 1}\\\\=2300

The sample space for selecting the group to test contains <u>2,300</u> elementary events.

6 0
3 years ago
Which number has a value of 800,000,000
Igoryamba
A.890,380,986 of the value
4 0
3 years ago
HELP ME PLEASE NEED ANSWER NOWWWWWWWWWW solve the following system of equation. Round your answer to the nearest tenth. Your ans
dlinn [17]
 
(A) 5x+2y=21
(B) -2x+6y=-34

multiply (A) by - 3→ -15x - 6y = - 63 (C)

Now add (C) to (B):

-15x - 6y = - 63 (C)
-2x + 6y  =-34 (B)
 -----------    --------
-17x         = - 97       and x = 97/17

Now replace x value in any of the equation and you'll find y = - 64/17

1st Answer (97/17 , - 64/17)
2nd Answer : 97/17 + (-64/17) = 97/17 - 64/17 = 33/17 ≈ 2

7 0
3 years ago
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