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Bess [88]
4 years ago
10

Which points in the scatter plot are outliers?

Mathematics
2 answers:
marysya [2.9K]4 years ago
8 0
F and K are the answers.
svetlana [45]4 years ago
5 0
F and K are definitely outliers of the plot
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Which statement must be true about the diagram?
KATRIN_1 [288]

the answer is C (Ray km is an angle bisector of <NKL)

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PLZ help me with this :(
Kaylis [27]

Explanation:

Level 2

Part 1: √250 would be simplified to 5√10, because you need to find two factors that equal 250. 25 multiplied by 10 are two factors that you can utilize. Because 25 is a perfect square, it could be reduced to 5. Because 10 isn't a perfect square, you leave it as a radical.

Part 2: √250 is an irrational number because it's a non-terminating decimal and you cannot convert it into a fraction, so it wouldn't be rational.

Level 3

Part 1: √150x^5 would be simplified to 5x^2√6x. Again, find two factors that equal the product, 150. 25 multiplied by 6 are two factors that are useable. Just like the first question, 25 is a perfect square, so it can be reduced to 5. 6 is not a perfect square, so you would leave as a radical. Now, moving onto x^5. You can factor out x^4, because it's a perfect square. x^4 can become x^2. Move x^2 next to 5 and x would be left in the radical with 6.

Part 2: It's rational because 2√4 is simply just 2 x 2 because √4 is a perfect square. 4+7=11. 11 can be converted into a fraction, so it wouldn't be irrational.

Level 4

Part 1: 13√750x*5 y*8 would be simplified to 65x^2y^4√30x. Find two factors that equal 750, which are 25 and 30. You know the drill, 25 is reduced to 5 and 30 stays as a radical. Multiply 13 and 5 to get 65. Factor out x^4 out of x^5 to get x^2. x^8 is a perfect square that can be reduced to x^4.

Part 2: Two unique expressions are 4√16+3 and 5√8 x 34. √16 is a perfect square, so it can become 4. 4 x 4 is 16 and 16 + 3 = 19. 19 is a rational number. 5√8 is irrational, so right off the bat, you'll know it's an irrational expression.

8 0
3 years ago
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raketka [301]

Answer:

Given f(x) = 2x + 3 and g(x) = –x2 + 5, find (g o f )(x).

(g o f )(x) = g( f(x))

   = g(2x + 3)

   = –(           )2 + 5    ... setting up to insert the input

   = –(2x + 3)2 + 5

   = –(4x2 + 12x + 9) + 5

   = –4x2 – 12x – 9 + 5

   = –4x2 – 12x – 4

Step-by-step explanation:

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