X^2+y^2=z^2
x^2+96^2=100^2
x=sqrt(100^2-96^2)
x=28 so the distance from the base of the ladder and the base of the ladder is 28ft.
Hope this helps. Any questions please just ask. Thank you.
Answer:
Either, (9+√69)/6 or (9-√69)/6
Step wise:
3x²-9x+1=0-------------------(i)
comparing equation onw with (ax²+bx+c=0), we get,
a=3, b=-9, c=1
now,
using Quadratic Formula,
(-b±√b²-4ac)/2a=x
{-(-9)±√(-9)²-4.3.1}/2.3=x
(9±√81-12)/6=x
(9±√69)/6=x
Taking +(ve) sign Taking -(ve) sign
(9+√69)/6=0 (9-√69)/6=0
∴(9+√69)/6=0 ∴(9-√69)/6=0
[∵They cannot be further solved]
Answer:
the slope is -3
Step-by-step explanation:
Answer:
A and E
Step-by-step explanation:
