Answer:
x < 10
Step-by-step explanation:
2x-8 <12
Add 8 to each side
2x-8+8 <12+8
2x< 20
Divide by 2
2x/2 < 20/2
x < 10
The simple way of calculating a perimeter is to add all of the sides.
For a rectangle this would equal 2 x length + 2 x width
P = 2(6x + 3) + 2(-2x - 5)
= 12x + 6 - 4x - 10
= 8x - 4
At a higher level both the length and width must be greater than zero (= zero is a trivial rectangle)
6x + 3 > 0
6x > -3
x > -0.5
-2x - 5 > 0
2x + 5 < 0 (multiplying by -1 reverses the inequality)
2x < -5
x < -2.5
This rectangle cannot exist as x cannot be < -2.5 and > -0.5 at the same time!
Answer:
vertical asymptote is: x=4
horizontal asymptote is: y=1
pls mark as brainliest :)
