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3 years ago

0.66x10 to the 3rd power

Mathematics

2 answers:

11111nata11111 [884]3 years ago

7 0

Answer:

660

Step-by-step explanation:

0.66 x 10^3, you move the decimal point to the front three times and you get 660

Bas_tet [7]3 years ago

4 0

The answer to this is 660

You might be interested in

Of 1000 randomly selected cases of lung cancer, 823 resulted in death within 10 years.

Arada [10]

Answer:

a) $0.823 - 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.799$

$0.823 + 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.847$

The 95% confidence interval would be given by (0.799;0.847)

b) $n=\frac{0.823(1-0.823)}{(\frac{0.03}{1.96})^2}=621.79$

And rounded up we have that n=622

c) $n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11$

And rounded up we have that n=1068

Step-by-step explanation:

Part a

$\hat p=\frac{823}{1000}=0.823$

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by:

$z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96$

The confidence interval for the mean is given by the following formula:

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$

If we replace the values obtained we got:

$0.823 - 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.799$

$0.823 + 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.847$

The 95% confidence interval would be given by (0.799;0.847)

Part b

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And on this case we have that $ME =\pm 0.03$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

And replacing into equation (b) the values from part a we got:

$n=\frac{0.823(1-0.823)}{(\frac{0.03}{1.96})^2}=621.79$

And rounded up we have that n=622

Part c

$n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11$

And rounded up we have that n=1068

5 0

3 years ago

Find the distance between <img src="https://tex.z-dn.net/?f=%5Cfrac%7B7%7D%7B12%7D" id="TexFormula1" title="\frac{7}{12}" alt="\

jek_recluse [69]

Answer:

5/36

Explanation:

Distance on a number line is basically difference between two numbers. So we subtract the two numbers. This can be solved on a calculator btw. 7/12 - √16/81 = 5/36.

3 0

2 years ago

2 = 81 please help lol

djverab [1.8K]

Answer:

40.5 is what they are divided

Step-by-step explanation:

4 0

3 years ago

66/100 simplest friend

tamaranim1 [39]

Assuming you mean simplified, 66/100=33/50, which can be achieved by dividing both the numerator and denominator by 2.