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grin007 [14]
3 years ago
7

In a triangle, two of the angles measure 63�� and 71��. find the measure of the third angle.

Mathematics
1 answer:
Delicious77 [7]3 years ago
8 0
Since a triangle's angles must all together measure 180 degrees, subtract the two angles from 180: 180 - 71 - 63 = 46
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00:00
vaieri [72.5K]

Answer:

(D)What did Micah eat for lunch yesterday?

Step-by-step explanation:

A statistical question is a question for which the expected response varies. That is, we do not expect to get a single answer. Out of the given options,

Option D is not a valid statistical question as the response to the question will always be the same for a particular day,

If Micah ate cheesecakes for lunch yesterday, asking repeated times will not change the response.

6 0
3 years ago
Help? Thanks!!!!!!!! If possible show work please!
FrozenT [24]

Answer:

B =102

Y = 32

Step-by-step explanation:

Solving (47):

To solve for B, we have:

B + 50 + 28 = 180 --- sum of angles in a triangle

This gives

B + 78 = 180

Collect like terms

B =- 78 + 180

B =102

Solving (48):

To solve for Y, we have:

X + Y+ Z = 180 --- sum of angles in a triangle

This gives

Y = 180 - X - Z

Where

W+ X=180 -- angle on a straight line

Solve for X

X=180 -W

X=180 -100 = 80

So, we have:

Y = 180 - X - Z

Y = 180 - 80 - 68

Y = 32

5 0
3 years ago
I need to find the greatest common factor of <img src="https://tex.z-dn.net/?f=40s%5E3t%5E5" id="TexFormula1" title="40s^3t^5" a
solong [7]

Answer:

\large\boxed{GCF(40s^3t^5,\ 2s^4t^4,\ 14s^6t^6)=2s^3t^4}

Step-by-step explanation:

40s^3t^5=\boxed2\cdot2\cdot2\cdot5\cdot \boxed{s\cdot s\cdot s}\cdot \boxed{t\cdot t\cdot t\cdot t}\cdot t\\\\2s^4t^4=\boxed2\cdot  \boxed{s\cdot s\cdot s}\cdot s\cdot \boxed{t\cdot t\cdot t\cdot t}\\\\14s^6t^6=\boxed2\cdot7\cdot  \boxed{s\cdot s\cdot s}\cdot s\cdot s\cdot s\cdot \boxed{t\cdot t\cdot t\cdot t}\cdot t\cdot t\\\\GCF(40s^3t^5,\ 2s^4t^4,\ 14s^6t^6)=\boxed2\cdot  \boxed{s\cdot s\cdot s}\cdot\boxed{t\cdot t\cdot t\cdot t}=2s^3t^4

7 0
3 years ago
Solve the following system of equations.
Elan Coil [88]

Answer:

(2,-3)

Step-by-step explanation:

I am not sure if you meant the first equation to be y or -y.  I solved it as y.

y = x-5                       -x -3y =7

I am going to take the second equation and write it as x =

-x - 3y = 7  Give equation

-x = 3y +7   Add 3y to both sides

x = -3y-7  Multiplied each term in the equation by -1 so that x could be positive

I am going to substitute -3y-7 for x in the first equation up above

y = x - 5

y = -3y -7 - 5  Substitute -3y-7 for x

y = -3y -12  Combined -7-5

4y = -12  Added 3y to both sides

y = -3  Divided both sides by 4.

I now know that y is -3, I will plug that into x = -3y-7 to solve for x

x = -3(-3) -7

x = 9-7   A negative times a negative is a positive

x = 2

5 0
2 years ago
Gavin goes for a run at a constant pace of 9 minutes per mile. Ten minutes later, Lars goes for a run, along the same route, at
sweet [91]

Answer:  The answer is 35 minutes.


Step-by-step explanation:  Given that Gavin goes for a run at a constant pace of 9 minutes per mile and after 10 minutes, Lars started running along the same route, at a constant pace of 7 minutes per mile. We need to find the number of minutes Lars will take to reach Gavin.

In 9 minutes, distance run by Gavin = 1 mile.

So, in 1 minute, distance travelled by Gavin will be

d_G=\dfrac{1}{9}=\dfrac{7}{63}~\textup{miles}.

Similarly,

In 7 minutes, distance run by Lars = 1 mile.

So, in 1 minute, distance travelled by Lars will be

d_L=\dfrac{1}{7}=\dfrac{9}{63}~\textup{miles}.

Now, since Lars started after 10 minutes, so distance run by Gavin in those 10 minutes will be

d_{G10}=\dfrac{10}{9}=\dfrac{70}{63}~\textup{miles}.

Now, difference between Lars and Gavin's rate of runnings is

\dfrac{9}{63}-\dfrac{7}{63}=\dfrac{2}{63}.

Therefore, the time taken by Lars to reach Gavin is given by

t=\dfrac{\frac{70}{63}}{\frac{2}{63}}=35.

Thus, the required time is 365 minutes.  


6 0
3 years ago
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