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3 years ago

Solve the equation for b

Mathematics

2 answers:

Alona [7]3 years ago

6 0

Answer:

b=7a

Step-by-step explanation:

11a+b/3=6a

or, 11a+b=6a*3( when there is divide in one side it will be multiply when it is in another side)

or, 11a+b=18a(multiplying the number)

or, b=18a-11a( when there is + sign in one side it will be - sing in another side )

or, b=7a

Keith_Richards [23]3 years ago

5 0

Answer:

D. b=7a

Step-by-step explanation:

Add -11/3a to both sides.

$\frac{1}{3}b=\frac{7}{3}a$

Divide both sides by 1/3

1 /3 b ÷1/ 3 = 7/ 3 ÷a 1 /3

and the answer is

b=7a

ik this doesnt make any sense but hope this helps

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fter production, a computer component is given a quality score of A, B, and C. On the average U of the components were given a q

RoseWind [281]

Answer:

Follows are the solution to this question:

Step-by-step explanation:

In the given question some of the data is missing so, its correct question is defined in the attached file please find it.

Let

A is quality score of A

B is quality score of B

C is quality score of C

$\to P[A] =0.55\\\\\to P[B] =0.28\\\\\to P[C] =0.17\\$

Let F is a value of the content so, the value is:

$\to P[\frac{F}{A}] =0.15\\\\\to P[\frac{F}{B}] =0.12\\\\\to P[\frac{F}{C}] =0.14\\$

Now, we calculate the tooling value:

$\to p[\frac{C}{F}]$

using the baues therom:

$\to p[\frac{C}{F}] = \frac{p[C] \times p[\frac{F}{C} ]}{p[A] \times p[\frac{F}{A}] + p[B] \times p[\frac{F}{B}]+p[C] \times p[\frac{F}{C}] }$

$= \frac{ 0.17 \times 0.14 }{0.55 \times 0.15 + 0.28 \times 0.12 + 0.17 \times 0.14 } \\\\= \frac{0.0238}{0.0825 + 0.0336 + 0.0238} \\\\= \frac{0.0238}{0.1399} \\\\=0.1701$