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Kazeer [188]
3 years ago
9

which values of x and y are solutions to the open sentence? 4y ≥ 3x 2 a. x = 3, y = 0 b. x = 4, y = 3 c. x = 6, y = 5 d. x = 7,

y = 5
Mathematics
1 answer:
boyakko [2]3 years ago
8 0
4y ≥ 3x + 2

Plugging in the values in the options, then the required values are when x = 6 and y = 5, then
4(5) ≥ 3(6) + 2
20 ≥ 18 + 2
20 ≥ 20
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lozanna [386]

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5 0
3 years ago
Drag tiles to fill in the blanks to complete the expression that could be used to predict the number of winners of a game. Tiles
ziro4ka [17]

Answer:

First blank - A)Total Number of Possible Outcomes

Second blank - B)Number of Winners

Step-by-step explanation:

The exact question is as follows :

We know that,

Probability of an event is equals to Total number of Favorable outcomes divided by Total number of outcomes

So,

P(event) = Number of favorable outcomes ÷ Total Number of Possible Outcomes

As we have to predict the Number of winners of a game

So,

P(Number of winner) = Number of winners ÷ Total number of Contestants

∴ we get

P(event) = Number of favorable outcomes ÷ Total Number of Possible  Outcomes

             = Number of winners ÷ Total number of Contestants

4 0
3 years ago
A coin is tossed and a single 6 sided number cube is rolled. Find the probability of landing on the heads side of the coin and r
Delicious77 [7]

Answer:

The probability of landing on the heads side of the coin and rolling 3 on the number cube is 0.083.

Step-by-step explanation:

Given:

Coin is tossed and a single 6 sided number cube is rolled.

Let the event of tossing head be 'H' and event of rolling a 3 be 'R3'.

Now, we know that:

Probability of an event 'A' = Favorable outcomes of 'A' ÷ Total possible outcomes

Now, for tossing a coin, the total possible outcomes are head and tail. So, there are 2 possible outcomes.

So, probability of event 'H' is given as:

P(H)=\dfrac{n(H)}{n(S)}\\\\P(H)=\frac{1}{2}=0.5

Similarly, for rolling a 6 sided cube, the possible outcomes are numbers 1 to 6. So, the number of possible outcomes is, n(S)=6

Now, probability of rolling a 3 is given as:

P(R3)=\frac{n(R3)}{n(S)}\\\\P(R3)=\frac{1}{6}

Now, both the events 'H' and 'R3' occur together. So, the combined probability is the product of two individual probabilities as they are independent events. So,

P(H\ and\ R3)=P(H)\times P(R3)\\\\P(H\ and\ R3)=\frac{1}{2}\times \frac{1}{6}\\\\P(H\ and\ R3)=\frac{1}{12}=0.083

Note: Independent events are those events whose intersection is an empty set of events or the outcome of one event doesn't affect the outcome of the other event.

Therefore, the probability of landing on the heads side of the coin and rolling 3 on the number cube is 0.083.

4 0
3 years ago
each day alyssa jogs for 25 minutes on a treadmill she jogs 135 meters a minute at the speed at which alyssa is jogging how many
Fittoniya [83]

Answer: she is jogging 2.25 i think

Step-by-step explanation:

im sorry im not sure i just divided 135 by 60 but i dont think its right:(

5 0
3 years ago
What is the last one number 12
rosijanka [135]
What is the last one number 12
8 0
3 years ago
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