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emmainna [20.7K]
3 years ago
15

Dylan uses the expressions (x2 – 2x + 8) and (2x2 + 5x – 7) to represent the length and width of his bedroom. Which expression r

epresents the area (lw) of Dylan's room?
Mathematics
2 answers:
balu736 [363]3 years ago
7 0

Answer:

2x^4+ x^3 - x^2 + 54x - 56 expression represents the area of Dylan’s room

Step-by-step explanation:

C on edge :)

lawyer [7]3 years ago
6 0

Answer:

2x⁴+x³-x²+54x+56

Step-by-step explanation:

Given the expression length of dylan room =  (x² – 2x + 8) and width = (2x² + 5x – 7), assuming the shap of the room is rectangular in nature, the formula for calculating area of a triangle is given as;

Area of rectangle = Length *Width

Area of the rectangle =  (x² – 2x + 8)(2x² + 5x – 7)

Area of the rectangle  = x²(2x² + 5x – 7) - 2x (2x² + 5x – 7) + 8(2x² + 5x – 7)

= (2x⁴+5x³-7x²)-(4x³+10x²-14x)+(16x²+40x-56)

expanding the bracket

= 2x⁴+5x³-7x²-4x³-10x²+14x+16x²+40x-56

Collecting the like terms;

= 2x⁴+5x³-4x³-7x²-10x²+16x²+40x+14x+56

= 2x⁴+x³-x²+54x+56

Hence, the expression that represents the area (lw) of Dylan's room is 2x⁴+x³-x²+54x+56

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<h3>Answer:   C) 4/8 = 0.5</h3>

=========================================================

Explanation:

The sine ratio involves the opposite over hypotenuse.

With respect to reference angle J, the opposite leg is the one furthest from the angle. So the opposite side is KL = 4. The hypotenuse is always the longest side, always opposite the 90 degree angle, so LJ = 8 is the hypotenuse.

sin(angle) = opposite/hypotenuse

sin(J) = KL/LJ

sin(J) = 4/8

sin(J) = 0.5

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Answer:

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Step-by-step explanation:

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The formula for the area A of a rectangle with length l and width w is A = l ⋅ w . Find A if: l = 23 feet and w = 15 feet The ar
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Step-by-step explanation:

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3 0
4 years ago
Multiply the polynomials show steps
Karo-lina-s [1.5K]

Answer:

3a^{4} + 11a³ - 7a² + 18a - 18

Step-by-step explanation:

<u>When multiplying with two brackets, you need to multiply the three terms, (a²), (4a) and (-6) from the first bracket to all the terms in the second brackets, (3a²), (-a) and (3) individually. I have put each multiplied term in a bracket so it is easier.</u>

(a² + 4a - 6) × (3a² - a + 3) =

(a² × <em>3a²</em>) + {a² × <em>(-a)</em>} + (a² × <em>3</em>) + (4a × <em>3a²</em>) + {4a × <em>(-a)</em>} + (4a × <em>3</em>) + {(-6) × <em>a²</em>) + {(-6) × <em>(-a)</em>} + {(-6) × <em>3</em>}

<u>Now we can evaluate the terms in the brackets. </u>

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<u>Evaluate like terms.</u>

3a^{4} -a³ + 3a² + 12a³ -4a² + 12a -6a² + 6a -18 = 3a^{4} + 11a³ - 7a² + 18a - 18

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Answer:

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Step-by-step explanation:

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