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2 years ago

7

Help trying to get this done to graduate i know it may seem easy but i feal lime im missing sumthing

2 answers:

MrRissso [65]2 years ago

4 0

I believe the answer is y=3x+4
Hope this helps!

yaroslaw [1]2 years ago

3 0

Well, you can find the equation using the two points that are given: (4,1) and (0,3). The answer should probably be in slope intercept form: y=mx+b. M is the slope and b is the y intercept.
The first step is to find the slope which is y1-y2 over x1-x2. This would equal 2.
Since we already know the y intercept, we just plug it in.
y=2x+3

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Instructions: Given the preimage and image, find the dilation scale factor.

Elanso [62]

Answer:

2

Step-by-step explanation:

The shape expanded in size by a factor of 2. So the dilation scale factor is 2

3 0

2 years ago

How can i prove this property to be true for all values of n, using mathematical induction.

chubhunter [2.5K]

Proof -

So, in the first part we'll verify by taking n = 1.

$\implies \: 1 = {1}^{2} = \frac{1(1 + 1)(2 + 1)}{6}$

$\implies{ \frac{1(2)(3)}{6} }$

$\implies{ 1}$

Therefore, it is true for the first part.

In the second part we will assume that,

$\: { {1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} = \frac{k(k + 1)(2k + 1)}{6} }$

and we will prove that,

$\sf{ \: { {1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} + (k + 1)^{2} = \frac{(k + 1)(k + 1 + 1) \{2(k + 1) + 1\}}{6}}}$

$\: {{1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} + (k + 1)^{2} = \frac{(k + 1)(k + 2) (2k + 3)}{6}}$

${1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} + (k + 1)^{2} = \frac{k (k + 1) (2k + 1) }{6} + \frac{(k + 1) ^{2} }{6}$

${1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} + (k + 1)^{2} = \frac{k(k+1)(2k+1)+6(k+1)^ 2 }{6}$

${1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} + (k + 1)^{2} = \frac{(k+1)\{k(2k+1)+6(k+1)\} }{6}$

${1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} + (k + 1)^{2} = \frac{(k+1)(2k^2 +k+6k+6) }{6}$

${1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} + (k + 1)^{2} = \frac{(k+1)(2k^2+7k+6) }{6}$

${1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} + (k + 1)^{2} = \frac{(k+1)(k+2)(2k+3) }{6}$

<u>Henceforth, by </u><u>using </u><u>the </u><u>principle </u><u>of </u><u> mathematical induction 1²+2² +3²+....+n² = n(n+1)(2n+1)/ 6 for all positive integers n</u>.

_______________________________

<em>Please scroll left - right to view the full solution.</em>

8 0

1 year ago

What’s 10-8+434+87+64

attashe74 [19]

It is 587
i trust my calculator

5 0

3 years ago

Read 2 more answers

13. A packet of sweets costs $2.45.

Margaret [11]

Answer:

$2.45*4/7=$1.4

So felipe gets $1.4

Step-by-step explanation:

$2.45*4/7=$1.4

So felipe gets $1.4

4 0

2 years ago

Which expression is equivalent to (4+6i)^2

Talja [164]

answer is A.) -20+48i

hope this helps

3 0

2 years ago