We have been given an equation of circle
. We are asked to find the center and radius of the circle.
First of all, we will write equation of circle is standard form
, where center of circle is at point (h,k) and radius is r.
Let us complete the square for both x and y.


Adding half the square of coefficient of x and y term, we will get:





Therefore, the center of the circle is
and radius is 4 units.
The 14th term is equal to -44.
y = 12 - 5x
The sequence can be represented by this function.
Each term is being subtracted by 5.
Using this function we can find the 14th time.
y = 12 - 5(14)
y = 12 - 56
y = -44
Hello!
Explanation:
First, you had to do is multiply by the numbers. And don't forget to used variables.




Answer: → 
Hope this helps!
Thanks!
-Charlie