The answer to the question
Michael took the return trip at a velocity 33.75 miles per hour.
<h3>How fast did Michael drive in his return trip?</h3>
Let suppose that Michael drove in <em>straight line</em> road and at <em>constant</em> velocity. Therefore, the speed of the vehicle (v), in miles per hour, can be defined as distance traveled by the vehicle (d), in miles, divided by travel time (t), in hours.
First trip
45 = s / 3 (1)
Second trip
v = s / 4 (2)
By (1) and (2):
45 · 3 = 4 · v
v = 33.75 mi / h
Michael took the return trip at a velocity 33.75 miles per hour.
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Answer:



Step-by-step explanation:
Number of Men, n(M)=24
Number of Women, n(W)=3
Total Sample, n(S)=24+3=27
Since you cannot appoint the same person twice, the probabilities are <u>without replacement.</u>
(a)Probability that both appointees are men.

(b)Probability that one man and one woman are appointed.
To find the probability that one man and one woman are appointed, this could happen in two ways.
- A man is appointed first and a woman is appointed next.
- A woman is appointed first and a man is appointed next.
P(One man and one woman are appointed)

(c)Probability that at least one woman is appointed.
The probability that at least one woman is appointed can occur in three ways.
- A man is appointed first and a woman is appointed next.
- A woman is appointed first and a man is appointed next.
- Two women are appointed
P(at least one woman is appointed)

In Part B, 
Therefore:
