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3 years ago

14

A house and a lot are appraised at 212,400. If the value of the house is five times the value of the lot, how much Is the house

worth

2 answers:

seropon [69]3 years ago

7 0

If the lot is 5 times more than there are 6 amounts that are the same that add up to be 212,400. so 212,400/6 is 35,400. since the house is 5 times more than the lot we take 35,400 and multiply it by 5 which is 177,000 the value of the house. We can check our answer by adding 35,400 to our 177,000 and we get 212400

vazorg [7]3 years ago

5 0

Answer:

$177,000

Step-by-step explanation:

Let x represent value of lot.

We have been given that the value of the house is five times the value of the lot. The value of house would be $5x$ .

We have been given that a house and a lot are appraised at 212,400. We can represent this information in an equation as:

$x+5x=212,400$

$6x=212,400$

$\frac{6x}{6}=\frac{212,400}{6}$

$x=35,400$

Now, we will substitute $x=35,400$ in expression $5x$ .

$5x=5(35,400)=177,000$

Therefore, the house is worth $177,000.

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3 years ago

For every 45 vehicles up past 15 are many vans so how many minivans would pass if there were 60 vehicles

Colt1911 [192]

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7 0

4 years ago

The volume of a 10 ounce box of cheerios is 258.75in3. the length of the box is 4 inches less than the height and the width is 3

Marina86 [1]

Answer:

Height of the box = 11.5 in

Step-by-step explanation:

Let h be the height of the box.

Assuming the volume of the Box is $258.75\ in^3$ .

Given:

Length = Height - 4 = h - 4

Width = 3 in

We need to find the height of the box.

Solution:

We know that the volume of the box.

$Volume = Length\times height\times width$

Substitute all given value in above formula.

$258.75 = (h-4)\times h\times 3$

Rewrite the equation as:

$258.75 = 3h(h-4)$

$258.75 = 3h^2-12h$

$3h^2-12h-258.75=0$

whole equation divided by 3.

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Use quadratic formula with $a = 1, b = -4,c=-86.25$

$h=\frac{-b\pm \sqrt{(b)^{2}-4ac}}{2a}$

Put these a, b and c value in above equation.

$h=\frac{-(-4)\pm \sqrt{(-4)^{2}-4(1)(-86.25)}}{2(1)}$

$h=\frac{4\pm \sqrt{16+345}}{2}$

$h=\frac{4\pm \sqrt{361}}{2}$

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For positive sign

$h=\frac{23}{2}$

h = 11.5 in

For negative sign

$h=\frac{-15}{2}$

h = -7.5

We take positive value of h.

Therefore, the height of the box h = 11.5 in

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