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2 years ago

11

-1 - (-16) plz find the absolute value of this!

2 answers:

djyliett [7]2 years ago

8 0

Answer:

16

Step-by-step explanation:

the absolute value is always it's distance away from 0 on a number like so -16 is 16 numbers away from 0 so it's 16 the that's the absolute number of digits -16 is away from 0

Bond [772]2 years ago

8 0

-1 + 16 = 15 <— like this or like -1 absolute value is -1 which is 1 minus the absolute of -16 which is 16 as in —> 1 - 16 =- -15 and -15 absolute value would be 15

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Answer:

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Step-by-step explanation:

x, y are the numbers

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x×y = 39

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5y² + 2y - 39 = 0

the solution of a quadratic equation :

y = (-b ± sqrt(b² - 4ac))/2a

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Let x be a random variable representing percentage change in neighborhood population in the past few years, and let y be a rando

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Answer:

$m=\frac{2506.833}{604.833}=4.1447$

Nowe we can find the means for x and y like this:

$\bar x= \frac{\sum x_i}{n}=\frac{77}{6}=12.833$

$\bar y= \frac{\sum y_i}{n}=\frac{587}{6}=97.833$

And we can find the intercept using this:

$b=\bar y -m \bar x=97.833-(4.1447*12.833)=44.644$

So the line would be given by:

$y=4.1447 x +44.644$

Step-by-step explanation:

$m=\frac{S_{xy}}{S_{xx}}$

Σx = 77, Σy = 587, Σx2 = 1593, Σy2 = 70,533, and Σxy = 10040.

Where:

$S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}$

$S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}$

With these we can find the sums:

$S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}=1593-\frac{77^2}{6}=604.833$

$S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i){n}}=10040-\frac{77*587}{6}=2506.833$

And the slope would be:

$m=\frac{2506.833}{604.833}=4.1447$

Nowe we can find the means for x and y like this:

$\bar x= \frac{\sum x_i}{n}=\frac{77}{6}=12.833$

$\bar y= \frac{\sum y_i}{n}=\frac{587}{6}=97.833$

And we can find the intercept using this:

$b=\bar y -m \bar x=97.833-(4.1447*12.833)=44.644$

So the line would be given by:

$y=4.1447 x +44.644$

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3 years ago