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dolphi86 [110]
3 years ago
8

the radius of a circle is 10 centimeters. what is the area of a sector bounded by a 90° arc? give the exact answer in simplest f

orm

Mathematics
2 answers:
alina1380 [7]3 years ago
7 0
If the radius of the circle is 10 centimeters, the formula to get the area would be \pi r^2, and that would give us the area of 100 \pi square centimeters. \frac{360}{90} would give us 4, so \frac{100}{4} would give us the answer of 25 square centimeters. 

I hope this helped!!! ^^

Alex787 [66]3 years ago
6 0
I hope this isn't too late! You can find the answer to this by first finding the area of the circle, A=πr². So since the radius is 10, we input that into the equation to get π100. Now, there is 360° in a circle and a sector of 90° is 1/4 of it. So to answer the question all you have to do is find 1/4 of the area of the circle. 

The answer is π25.

To solve the other questions on your assignment just think about how much the sector is of the full 360° of the circle, for example 180° is 1/2 of the circle or 270° is 3/4 of the circle, and multiply the fraction by the area of the circle.

Hope this helped, good luck! :)
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The probability distribution of the amount of memory X (GB) in a purchased flash drive is given below. x 1 2 4 8 16 p(x) .05 .10
Rama09 [41]

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a) E(X) = 6.45

b) E(X^{2} )= 57.25

c) V(X) = 15.648

d) E(3X + 2) = 21.35

e) E(3X^{2} +2) = 173.75

f) V(3X+2) = 140.832

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h) V(X+1) = 15.648

Step-by-step explanation:

a) E(X) = \sum xP(x)

E(X) = (1*0.05) + (2*0.10) + (4*0.35) + (8*0.40) + (16*0.10)\\E(X) = 6.45

b)

E(X^{2} ) = (1^{2} *0.05) + (2^{2} *0.10) + (4^{2} *0.35) + (8^{2} *0.40) + (16^{2} *0.10)\\  E(X^{2} )= 57.25

c)

V(X) = E(X^{2} ) - (E(X))^{2} \\V(X) = 57.25 - 6.45^{2} \\V(X) = 15.648

d)

E(3X+2) = 3E(X) + 2\\E(3X+2) = (3*6.45) + 2 \\E(3X+2) = 21.35

e)

E(3X^{2} +2) = 3E(X^{2} ) + 2\\E(3X^{2} +2) = (3*57.25) + 2 \\E(3X^{2} +2) = 173.75

f)

V(3X+2) = 3^{2} V(X)\\V(3X+2) = 9*15.648\\V(3X+2) = 140.832

g)

E(X+1) = E(X) + 1\\E(X+1) = 6.45 + 1\\E(X+1) =7.45

h)

V(X+1) = 1^{2} V(X)\\V(X+1) = 15.648

6 0
3 years ago
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