The new slope would now be 2 so y=2x-3
I believe the answer would be 1620
The formula for the area of a triangle is (base•height)/2
So 60(54) = 3240/2 = 1620
Please correct me if I am wrong have a good day!
<span> Position Value of Term. 1. 4. </span>2<span>. 8. 3. </span>12<span>. 4. 16. 5. </span>20<span>. What expression shows the ... 1 1. </span>2<span> -5. </span>3 1<span>. 4 -5. 5 1. </span>B). n an<span>. 1 </span>2<span>. </span>2<span> 8. 3 14. 4 </span>20<span>. 5 26. </span>C). n an<span>. 1 </span>2<span>. </span>2<span> -</span>2<span>. 3 -10. 4 -26 ... </span>Generalize<span>the </span>pattern<span> by </span>finding<span> an explicit formula for the </span>nth term<span>. A) </span>n2<span> + 5. </span>B<span>). 3n + 1. </span>C<span>). </span>2n<span> + 5. </span>D). (n<span> + </span><span>1)</span>
Answer:
The standard form is 8 y ⁵ - 17 y⁴ + 6 y³ +2 y² - 11
The degree of given polynomial is '5'
the co-efficient of y⁴ is '-17'
Step-by-step explanation:
Given standard form 2 y²+ 6 y³-11-17 y⁴+8 y⁵
<em>The form ax² + b x + c is called the standard form of the quadratic expression of 'x'.This is second degree standard form of polynomial.</em>
<em>The form ax⁵ + b x⁴ + c x³ +d x² +ex +f is called the standard form of the quadratic expression of 'x'.This is fifth degree standard form of polynomial</em>
now Given polynomial is 2 y²+ 6 y³-11-17 y⁴+8 y⁵
The standard form is
8 y ⁵ - 17 y⁴ + 6 y³ +2 y² - 11
<u><em>Conclusion</em></u>:-
<em>The degree of given polynomial is '5'</em>
<em>The co-efficient of y⁴ is '-17'</em>
<em> </em>
