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yaroslaw [1]
3 years ago
5

R over 5 minus 6 equals negative one

Mathematics
1 answer:
sdas [7]3 years ago
4 0

The answer will be 25 because 25/5 = 5 - 6= -1

hope this help

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5y+3+4x identify parts in an algebraic expression
Sphinxa [80]

Answer:

y and x are variables, the 5 in 5y is a coefficient so is the 4 in 4x, the 3 is called a constant

Step-by-step explanation:

7 0
3 years ago
Can someone help me find the fa tor of (128m^2n^5 - 200m^4n^3)? <br>​
Leona [35]

Answer:

8m^2n^3, 4n-5m, and 4n+5m

Step-by-step explanation:

128m^2n^5-200m^4n^3 <-- Given

m^2(128n^5-200m^2n^3) <-- Factor out m²

m^2n^3(128n^2-200m^2) <-- Factor out n³

8m^2n^3(16n^2-25m^2) <-- Factor out 8

8m^2n^3(4n-5m)(4n+5m) <-- Difference of Squares

Therefore, the factors are 8m^2n^3, 4n-5m, and 4n+5m

3 0
3 years ago
1 inch corresponds to 4ft, what is 2 1/4 inches converted to feet
Roman55 [17]

Answer:

9 feet

Step-by-step explanation:

2 1/4 can be written as an improper fraction 9/4

we are given:

1 inch ----> corresponds to 4 feet

hence,

2 1/4 inch ---> corresponds to 4 feet x 2 1/4 = 4 x (9/4) = 9 feet

5 0
4 years ago
As a cold front passed through an area, the temperature changed by an average of −4°F°
elixir [45]

Answer:

-20°F

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
At a dairy farm the ratio of adult milking cows to young calves was 9:2. If there were 234 adult milking cows at the farm, how m
jok3333 [9.3K]

Answer:

52 young calves

Step-by-step explanation:

At a dairy farm the ratio of adult milking cows to young calves was 9:2. If there were 234 adult milking cows at the farm, how many young calves were there?

The ration is given as:

adult milking cows to young calves

= 9 : 2

= 234 : x

= 9/2 = 234/x

x = Number of young calves

Cross Multiply

9 × x = 2 × 234

= x = 2 × 234/9

x = 468/9

x = 52

Hence, the number of young calves on the farm is 52.

7 0
3 years ago
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