All categories

3 years ago

Can you guys please help me? This is due tomorrow, thanks so much

Mathematics

1 answer:

wariber [46]3 years ago

4 0

Answer:

Graph given in Question 18 is a function and the graph given in Question 19 is not a function. Just check the attached figure.

Step-by-step explanation:

From the given graph of a relation, it is easy to establish whether the given relation is a function or not. In order to determine the nature of the relation, there is vertical line test. This test can be done by drawing any vertical line crossing the graph of the given relation. This vertical line has a constant x -a line having constant x.

If this vertical line crosses the graph multiple times, then we can determine that the relation would not be a function. It means the graph contains multiple values of y for a single value of x. This violates the condition of a relation to be a function. Hence, the relation would not be a graph.

But, if the vertical line crosses the graph only one time, then we can determine that the given relation would be a function. It means the graph does not contain multiple values of y for a single value of x.

Solution of the Graph given in Question 18:

From the given graph of a relation, that sounds like a circle. It means the relation shown in current graph is not a function. The reason is simple. If we draw a vertical line, then the line would cross the graph twice. Hence, the given graph of a relation is not a function.

Just check that the value of x=1 will have two y values i.e (1, 5) and (1, -1). Also, at origin, for a value of x = 0, there are multiple values of y. Hence, the graph is not a not a function, but just a relation. Just check the attached figure.

Solution of the Graph given in Question 19:

From the given graph of a relation, it is clear that the graph is a function. The reason is simple. If we draw a vertical line, then the line would cross the graph only one time. Hence, the given graph of a relation is a function.

Just check that the points (0, 0), (2, 3), (-1, 3), (-3, 3) and (1, -3) all make a function as each input value yields an exactly one output function. Hence, the given graph of the relation is a graph. Just check the attached figure.

Keywords: function, relation, ordered pairs, graph, vertical line test

Learn about the graph functions from brainly.com/question/4708956

#learnwithBrainly

You might be interested in

The value of a rare baseball card A appreciated by 20 percent over a five year period; over the next five years, the value plumm

lbvjy [14]

<h2>Answer:</h2>

Percent value of A with respect to Percent value of B is,

$30\%$

<h2>Step-by-step explanation:</h2>

In the question,

Let us say the value of the Baseball card A and B initially is = 100x

So, for Baseball card A in first 5 years percent increase = 20%

So,

Value after 5 years = 100x + 20% of 100x = 120x

After 5 more years,

Percent decrease = 50%

So,

Value at the end of 10 years = 120x - 50% of 120x = 60x

Now,

For Baseball card B, Percent increase in 10 years = 100%

So,

Value of card B = 100x + 100% of 100x = 200x

So,

Percent value of A with respect to Percent value of B is,

$\frac{60x}{200x}\times 100=30\%$

7 0

3 years ago

Please can someone help me

Fofino [41]

Answer:

a. 25%

b. 55%

c. 35%

Hope it helps you and pls mark as brainliest : )

4 0

3 years ago

Read 2 more answers

Please help me my parents don’t understand either

lakkis [162]

For every loaf of bread there are 4 flour used

6 0

3 years ago

In the transformation ABC A'B'C', the preimage of B' is ____. . a0

Misha Larkins [42]

Answer:

Pre image of B' is B

Step-by-step explanation:

Given:

ABC is a triangle

A transformation is done on ABC so that the image is A'B'C'.

Note that transformations are of various types such as dilation, vertical shift, horizontal shift, rotation about a point, reflection on a line, etc.

In any type of transformation, corresponding vertices will be matched. In other words, A will become A', B will become B' and C will become C'.

Because of the property of the transformation to keep images similar and also transforming correspondingly the vertices we get preimage of B' would be nothing but B itself.

8 0

3 years ago

SOMEONE PLEASEEEE HELPPPP

andrew11 [14]

Answer:

The triangles are not similar

Step-by-step explanation:

6 0

3 years ago

Can you guys please help me? This is due tomorrow, thanks so much​

Can you guys please help me? This is due tomorrow, thanks so much