3 years ago

How find derivative of function: y=arcsin(2x+1) ...?

1 answer:

3 0

$( \arcsin{x})'= \frac{1}{ \sqrt{1-x^2} } 
\\
\\ (\arcsin{(2x+1)})'= \frac{1}{ \sqrt{1-(2x+1)^2} } (2x+1)'= \frac{2}{ \sqrt{1-(4x^2+4x+1)} } =
\\
\\= \frac{2}{ \sqrt{-4x^2-4x} } =\frac{2}{ \sqrt{4x(-x-1} )} =\frac{2}{ 2\sqrt{x(-x-1} )} =\frac{1}{ \sqrt{x(-x-1} )}$

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grin007 [14]

Answer would be a (-1, ten-thirds) :)

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2 years ago

The average weight of full-grown beef cows is 1,470 pounds with a standard deviation of 230 pounds. if the weights are normally

creativ13 [48]

Answer: The percentile is 89

Step-by-step explanation:

This question can be solved using concept for t tables

In a normal distribution the curve. $\mu= 1470 , \sigma = 230, x=1750$

The relationship between z score, mean and standard deviation is given by

$x = \mu+z\sigma$

So the z value according to this is given by the formula

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From the z table we can infer that p value for z=+1.217 is 88.82

So 1750 is 89th percentile

To learn more about statistics, visit brainly.com/question/26352252

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1 year ago

If 3f(x) - f(1/x) = x^2 , what is the value of f(1/2)?<br>and it's from R-{0} to R obviously.

GarryVolchara [31]

Answer:

0.59375‬

Step-by-step explanation:

3f(x) - f(1/x) = x^2

x = 2: 3f(2) - f(1/2) = 2^2

x = 1/2: 3f(1/2) - f(2) = (1/2)^2

Let a = f(1/2) and b = f(2):

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3 years ago

6. Simplify the following a) - 36 12y b) 24a (-3a) c) 2a (-3) - 5ab d) 70y + 10 +34y - 8 7 Simplify

Dmitriy789 [7]

Answer:

a) 432y

b) -72a^2

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d) 104y-46

Step-by-step explanation:

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3 years ago