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Stolb23 [73]
3 years ago
12

A student used formulas to make tables for f(x) and g(x). If the student wants to correctly illustrate that a quantity increasin

g exponentially eventually exceeds a quantity increasing linearly, which statement about f(x) and g(x) must be true?
Mathematics
1 answer:
wlad13 [49]3 years ago
6 0

If f is a function, x is the input (an element of the domain), and f(x) is the ... During the Coordinate Algebra EOC assessment, a formula sheet will be available ... A student must have a final grade of at least 70% to pass the course and to earn

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(04.01)
katrin [286]
The third one, 2 to the power of 5 over 6

√2  * 3√2

convert from radical form to exponent form to solve for the same root
( x^m/n = n√x^m )

2^(1/2) * 2^(1/3)  
2^{3/6} * 2^{2/6} - find common denominator (6)
6√(2^3) * 6√(2^2)  - convert back to radical form 
6√(2^3 * 2^2)- combine

6<span>√(</span>2^5)
then convert to exponential form again
~ 2^5/6 ~

5 0
2 years ago
The Ms Jodi has 950 non fiction books. 40% of those books are about science topics and 30% are about history. How many books are
Bad White [126]

Step-by-step explanation:

well first you need to divide all the percents by 100.

40% = .40

30%= .30

and now you need to multiply those two by 950.

.40/950=4.20

.30/950=3.15

so ms jodi has about 3 books on history

8 0
2 years ago
Solve the inequality 3(x + 2) &gt; 0.
Murljashka [212]

Answer:

B.) x>-2

Step-by-step explanation

3 0
3 years ago
Read 2 more answers
What is number 61 and a step by step explaination please?
astra-53 [7]

1/3 ln(<em>x</em>) + ln(2) - ln(3) = 3

Recall that m\log_b(n)=\log_b(n^m), so

ln(<em>x</em> ¹ʹ³) + ln(2) - ln(3) = 3

Condense the left side by using sum and difference properties of logarithms:

\log_b(m)+\log_b(n)=\log_b(mn)

\log_b(m)-\log_b(n)=\log_b\left(\dfrac mn\right)

Then

ln(2/3 <em>x</em> ¹ʹ³) = 3

Take the exponential of both sides; that is, write both sides as powers of the constant <em>e</em>. (I'm using exp(<em>x</em>) = <em>e</em> ˣ so I can write it all in one line.)

exp(ln(2/3 <em>x</em> ¹ʹ³)) = exp(3)

Now exp(ln(<em>x</em>)) = <em>x </em>for all <em>x</em>, so this simplifies to

2/3 <em>x</em> ¹ʹ³ = exp(3)

Now solve for <em>x</em>. Multiply both sides by 3/2 :

3/2 × 2/3 <em>x</em> ¹ʹ³ = 3/2 exp(3)

<em>x</em> ¹ʹ³ = 3/2 exp(3)

Raise both sides to the power of 3:

(<em>x</em> ¹ʹ³)³ = (3/2 exp(3))³

<em>x</em> = 3³/2³ exp(3×3)

<em>x</em> = 27/8 exp(9)

which is the same as

<em>x</em> = 27/8 <em>e</em> ⁹

3 0
3 years ago
-3y = 2x - 9; x= -3, 0, 3
astraxan [27]
1.)-3y=2* -3-9
    -3y=-6-9
    -3y=-15
        y=5
    -3*5=-15
2.)-3y=2*0-9
    -3y=0-9
    -3y=-9
       y=3
     -3*3=-9
3.)-3y=2*3-9
    -3y=6-9
    -3y=-3
      y=1
     -3*1=-3
3 0
3 years ago
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