The third one, 2 to the power of 5 over 6
√2 * 3√2
convert from radical form to exponent form to solve for the same root
( x^m/n = n√x^m )
2^(1/2) * 2^(1/3)
2^{3/6} * 2^{2/6} - find common denominator (6)
6√(2^3) * 6√(2^2) - convert back to radical form
6√(2^3 * 2^2)- combine
6<span>√(</span>2^5)
then convert to exponential form again
~ 2^5/6 ~
Step-by-step explanation:
well first you need to divide all the percents by 100.
40% = .40
30%= .30
and now you need to multiply those two by 950.
.40/950=4.20
.30/950=3.15
so ms jodi has about 3 books on history
1/3 ln(<em>x</em>) + ln(2) - ln(3) = 3
Recall that
, so
ln(<em>x</em> ¹ʹ³) + ln(2) - ln(3) = 3
Condense the left side by using sum and difference properties of logarithms:


Then
ln(2/3 <em>x</em> ¹ʹ³) = 3
Take the exponential of both sides; that is, write both sides as powers of the constant <em>e</em>. (I'm using exp(<em>x</em>) = <em>e</em> ˣ so I can write it all in one line.)
exp(ln(2/3 <em>x</em> ¹ʹ³)) = exp(3)
Now exp(ln(<em>x</em>)) = <em>x </em>for all <em>x</em>, so this simplifies to
2/3 <em>x</em> ¹ʹ³ = exp(3)
Now solve for <em>x</em>. Multiply both sides by 3/2 :
3/2 × 2/3 <em>x</em> ¹ʹ³ = 3/2 exp(3)
<em>x</em> ¹ʹ³ = 3/2 exp(3)
Raise both sides to the power of 3:
(<em>x</em> ¹ʹ³)³ = (3/2 exp(3))³
<em>x</em> = 3³/2³ exp(3×3)
<em>x</em> = 27/8 exp(9)
which is the same as
<em>x</em> = 27/8 <em>e</em> ⁹
1.)-3y=2* -3-9
-3y=-6-9
-3y=-15
y=5
-3*5=-15
2.)-3y=2*0-9
-3y=0-9
-3y=-9
y=3
-3*3=-9
3.)-3y=2*3-9
-3y=6-9
-3y=-3
y=1
-3*1=-3