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3 years ago

The measure of the complement of the supplement of angle A is 28°. The measure in degrees of angle A is

Mathematics

1 answer:

Airida [17]3 years ago

4 0

You can put this solution on YOUR website!

Define your variables,

Let X be your Angle

Then 180 - X is your Supplement

and 90 - X is your complement

Now you need to put these into an equation, this particular word probled does not have the equal sign "IS" however, the word measure0-xs, is the same, so that is where your = sign will go.

Your Equation should be...

180-x=2*(90-x)+28

Distribute

180-x=180-2x=28

Subtract 180 From Both Sides and add 2X to Both Sides

X+=+28

Your angle is 28, the Supplement is 152 and your Complement is 62

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Find the equation of line passing through points A (1, 3) and B (3, 7).

Sidana [21]

Solution:

To find the equation of line passing through points A (1, 3) and B (3, 7).

we know that, to derive the equation of a line we first need to calculate the slope of the line. Slope m of a line at points $(x_{1} ,y_{1})$ and $(x_{2}, y_{2})$ is given by - $m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$ .

Slope of the line at point A(1,3) and B(3,7)

$m=\frac{7-3}{3-1}$ .

$m=\frac{4}{2}$ .

$m=2$ .

Equation of a line using a point and a slope , $y-y_{1}= m(x-x_1)$

$y-3= 2(x-1)$

$y-3= 2x-2$

$y= 2x-2+3$

$y= 2x+1$

The equation of line passing through points A (1, 3) and B (3, 7) : $y= 2x+1$

4 0

3 years ago

PLEASE HELP! I'll give 5 out of 5 stars, give thanks, and give as many points as I can.

Liula [17]

Answer:

$\boxed{\boxed{x=\dfrac{\pi}{3}\ \vee\ x=\pi\ \vee\ x=\dfrac{5\pi}{3}}}$

Step-by-step explanation:

$\cos(3x)=-1\iff3x=\pi+2k\pi\qquad k\in\mathbb{Z}\\\\\text{divide both sides by 3}\\\\x=\dfrac{\pi}{3}+\dfrac{2k\pi}{3}\\\\x\in[0,\ 2\pi)$

$\text{for}\ k=0\to x=\dfrac{\pi}{3}+\dfrac{2(0)\pi}{3}=\dfrac{\pi}{3}+0=\boxed{\dfrac{\pi}{3}}\in[0,\ 2\pi)\\\\\text{for}\ k=1\to x=\dfrac{\pi}{3}+\dfrac{2(1)\pi}{3}=\dfrac{\pi}{3}+\dfrac{2\pi}{3}=\dfrac{3\pi}{3}=\boxed{\pi}\in[0,\ 2\pi)\\\\\text{for}\ k=2\to x=\dfrac{\pi}{3}+\dfrac{2(2)\pi}{3}=\dfrac{\pi}{3}+\dfrac{4\pi}{3}=\boxed{\dfrac{5\pi}{3}}\in[0,\ 2\pi)\\\\\text{for}\ k=3\to x=\dfrac{\pi}{3}+\dfrac{2(3)\pi}{3}=\dfrac{\pi}{3}+\dfrac{6\pi}{3}=\dfrac{7\pi}{3}\notin[0,\ 2\po)$

7 0

4 years ago

Read 2 more answers

What is the factored form of y=x^3+3x^2-x-3 and what the zeros

PSYCHO15rus [73]

y = x³ + 3x² - x - 3
0 = x³ + 3x² - x - 3
0 = x²(x) + x²(3) - 1(x) - 1(3)
0 = x²(x + 3) - 1(x + 3)
0 = (x² - 1)(x + 3)
0 = (x² + x - x - 1)(x + 3)
0 = (x(x) + x(1) - 1(x) - 1(1))(x + 3)
0 = (x(x + 1) - 1(x + 1))(x + 3)
0 = (x - 1)(x + 1)(x + 3)
0 = x - 1 or 0 = x + 1 or 0 = x + 3
+ 1 + 1 - 1 - 1 - 3 - 3
1 = x or -1 = x or -3 = x

Solution Set: {-3, -1, 1}

3 0

3 years ago

Simplify the following completely, show all work. √-45

scoray [572]

Answer:

$3\sqrt{5}i$