Jasmine reduced the size of a triangle to a height of 4 in. What is the new width if it was originally 12 in wide and 16 in tall
1 answer:
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Answer:
Step-by-step explanation:
Let equal sides of an isosceles triangle = a inches
Base = inches
Perimeter = 32 inches
a + a + = 32
Subtract 2 from both sides
a = 12 inches
base =
= 6 + 2
Base = 8 inches
Answer:
The area of the second enlargement is 1,944 square inches
The area of the second enlargement is (3 squared) squared times the original area.
The ratio of the area of the first enlargement to the area of the original equals the square of the scale factor
Step-by-step explanation:
<u><em>Verify each statement</em></u>
1) The area of the first enlargement is 72 square inches.
The statement is false
Because
we know that
The original dimensions of the rectangle are
length 6 inches and width 4 inches
so
First enlargement
Multiply the original dimensions by a scale factor of 3
The area of the first enlargement is
2) The area of the second enlargement is 1,944 square inches
The statement is true
Multiply the dimensions of the first enlargement by a scale factor of 3
The area of the second enlargement is
3) The area of the second enlargement is (3 squared) squared times the original area.
The statement is true
Because
The original area is 24 square inches
4) The area of the second enlargement is 3 times the area of the first enlargement
The statement is false
Because
so
5) The ratio of the area of the first enlargement to the area of the original equals the square of the scale factor
The statement is true
Because
The square of the scale factor is 3^2=9
and the ratio is equal to