Question

Some number was divided into 104.13. This quotient was multiplied by 4, after which the resulting product was added to 5. Given this sum totaled to -41.8, find the initial number?

Answer 1

Answer:

The initial number is -1218.321.

Step-by-step explanation:

Let the initial number be 'x'.

The number 'x' is divided into 104.13.

So, we divide the number 'x' by 104.13. This gives,

$\dfrac{x}{104.13}$

Now, the quotient is multiplied by 4. So, this means we need to multiply 4 to the fraction above. This gives,

$\dfrac{x}{104.13}\times 4\\\\\frac{4x}{104.13}$

Now, 5 is added to the result. This gives,

$\frac{4x}{104.13}+5$

Now, as per question:

$\frac{4x}{104.13}+5=-41.8$

Now, solving for 'x', we add -5 both sides. This gives,

$\frac{4x}{104.13}+5-5=-41.8-5\\\\\frac{4x}{104.13}=-46.8\\\\4x=-46.8\times 104.13\\\\4x=-4873.284\\\\x=\frac{-4873.284}{4}=-1218.321$

Therefore, the initial number is -1218.321.