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madam [21]
3 years ago
7

Two cyclists leave city at same time, one going east and the other going west. The westbound cyclist bikes 3 mph faster than the

eastbound cyclist. If after 6 hours they are 162 miles apart, how fast is each cyclist riding?
Mathematics
1 answer:
Bumek [7]3 years ago
8 0

Speed of the east bound cyclist is 12 mph and the speed of west bound cyclist is 15 mph.

<u>Solution:</u>

Let us assume that x is speed of slower eastbound cyclist

So, x+3 will be the speed of faster westbound cyclist

We know that distance is the product of speed and time. That is,

\text{Distance}=\text{Speed}\times\text{Time}

West-bound DATA:

Rate of speed = x+3 mph ; Time = 6 hrs ; distance = 6(x+3) = 6x+18 miles

East-bound DATA:

Rate of speed = x mph ; time = 6 hrs. ; distance = 6x miles

On solving,

Distance apart = 162

\Rightarrow6x+18+6x = 162

\Rightarrow12x=162-18

\Rightarrow x=\frac{144}{12}\rightarrow x=12

So, the rate of speed of the east bound cyclist is 12 mph and the rate of speed of the west bound cyclist will be x+3=12+3=15 \text{ mph}

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